AutoJs源码-龙形线(1)

/* 软件作者：https://xuhss.com/oxox/pro */ "ui"; ui.layout( <vertical> <canvas id="board" layout_weight="1"/> </vertical> ); //尺寸 const size = 256; var i = 0 var o = [0, 0, 0] var paint = new Paint(); ui.board.on("draw", function(canvas) { //绘制背景色 //canvas.drawColor(colors.BLACK); //绘制分数 paint.setColor(colors.BLACK); paint.setTextSize(50); //canvas.drawText(degree.x); //toast(JSON.stringify(degree,null,4)) paint.setStrokeWidth(5); var offset = { x: 350, y: 1000 }; //偏移坐标 canvas.translate(offset.x, offset.y); //绘制围墙 //toast(JSON.stringify(cube.p1,null,4)) paint.setColor(colors.RED); paint.setStrokeWidth(3) i += 0.3 n = (Math.sin(i) / 2 + 0.5) * 10 koch(canvas, paint, 0, -500, 0, 500, n); }); function zero(num) { if (num < 0) { return -1 } else { return 1 } } //连线 function line(canvas, paint, x1, y1, x2, y2) { canvas.drawLine(x1, y1, x2, y2, paint); } //三轴矩阵旋转 function koch(canvas, paint, x0, y0, x1, y1, k) { var x2, y2 x2 = (x0-x1)/2-(y0-y1)/2+x1 /*由上面的运算可以得到其余三点 坐标的计算式*/ y2 = (x0-x1)/2+(y0-y1)/2+y1 if (k > 1) /*如果迭代次数大于1，就继续迭代下去，即执行以下程序*/ { koch(canvas, paint, x0, y0, x2, y2, k - 1); /*对以(x0, y0)和(x2, y2)为端点的线段作为初始线段进行迭代运算，以下类同*/ koch(canvas, paint, x1, y1, x2, y2, k - 1); } else { /*如果迭代次数等于1，停止迭代，画出迭代生成的图形*/ line(canvas, paint, x0, y0, x2, y2); /*对以(x0, y0)和(x2, y2)为端点的线段作为初始线段进行迭代运算，以下类同*/ line(canvas, paint, x1, y1, x2, y2); } }