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Kaiviti said...

import java.util.Scanner;

class exam
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);

System.out.println("Enter 5 numbers:");

int[] numbers = new int[5];
int sum = 0;
int max = numbers[0];
int min = numbers[0];

for(int i=0; i<5; i++){
numbers[i] = input.nextInt();
sum = sum + numbers[i];

if (numbers[i] > max){
max = numbers[i];
}
else if (numbers[i] < min){
min = numbers[i];
}

}

int average = sum / 5;

System.out.println("Sum: " + sum);
System.out.println("Average: " + average);
System.out.println("Max: " + max);
System.out.println("Min: " + min );
System.out.println("Display sorted data : " + numbers[0] );
}
}

How come the min is always displaying 0...Please can someone help me...Thanks in advance

Apr 20, 2016, 11:27:25 PM

Posted to How to find largest and smallest number from integer array - Java Solution