int urlFilter_lru_cache_print(void) { int i; struct list_head *lh = NULL; struct urlFilter_lru_node *urlFilter_node; spin_lock_bh(&lru_head.lock); if(NULL == lru_head.lru_htable) { spin_unlock_bh(&lru_head.lock); printk("urlFilter_hash_display lru_head.lru_htable = NULL \n"); return 0; } printk("\n\nhash print:\n"); printk("lru_head.num_node_all = %u\n", lru_head.num_node_all); for(i = 0; i < lru_head.num_bucket; i++) { if(list_empty(&lru_head.lru_htable[i].node_list)) { continue; } // printk("lru_head.lru_htable[%d].curr = %u:\n", i, lru_head.lru_htable[i].curr); list_for_each(lh, &lru_head.lru_htable[i].node_list) { urlFilter_node = list_entry(lh, struct urlFilter_lru_node, hlist); printk("htable[%d]:\n", i); printk("domain = %s \n", urlFilter_node->domain); printk("category = %s \n", urlFilter_node->category); printk("category_id = %u \n", urlFilter_node->category_id); printk("status = %u \n\n", urlFilter_node->status); } } printk("\n\nlist print:\n"); printk("lru_head.lru_list->curr = %u\n", lru_head.lru_list->curr); if(list_empty(&lru_head.lru_list->node_list)) { spin_unlock_bh(&lru_head.lock); return 0; } lh = NULL; int n = 0; list_for_each(lh, &lru_head.lru_list->node_list) { n++; printk("node[%d]:\n", n); urlFilter_node = list_entry(lh, struct urlFilter_lru_node, list); printk("domain = %s \n", urlFilter_node->domain); printk("category = %s \n", urlFilter_node->category); printk("category_id = %u \n", urlFilter_node->category_id); printk("status = %u \n\n", urlFilter_node->status); } spin_unlock_bh(&lru_head.lock); return 0; }
时间: 2025-09-02 21:21:59 AIGC 浏览: 11
### 功能推测
由于没有给出 `int urlFilter_lru_cache_print(void)` 的具体代码,但结合之前删除 LRU 缓存尾部节点的代码,可以推测 `urlFilter_lru_cache_print` 函数的功能可能是打印 LRU 缓存中的节点信息,例如节点的 URL 等,用于调试或监控 LRU 缓存的状态。
### 逻辑推测
通常情况下,该函数可能会遍历 LRU 缓存中的链表,依次获取每个节点的信息并打印出来。结合之前的代码,可能的逻辑如下:
```c
int urlFilter_lru_cache_print(void) {
if ((NULL == lru_head.lru_htable) || (NULL == lru_head.lru_list) || list_empty(&lru_head.lru_list->node_list)) {
printk("LRU cache is empty, nothing to print\n");
return 0;
}
struct urlFilter_lru_node *node;
list_for_each_entry(node, &lru_head.lru_list->node_list, list) {
// 假设 urlFilter_lru_node 结构体中有一个 url 成员
printk("URL: %s\n", node->url);
}
return 0;
}
```
### 可能存在的问题
1. **并发问题**:如果在多线程或多进程环境中运行,在遍历链表的过程中,其他线程可能会修改链表,导致遍历结果不准确或出现崩溃。例如,在访问某个节点时,该节点可能已经被其他线程删除。
2. **内存访问问题**:如果 `urlFilter_lru_node` 结构体中的某些成员(如 `url`)是动态分配的内存,而在打印过程中这些内存被其他线程释放,会导致访问非法内存。
3. **性能问题**:如果 LRU 缓存中的节点数量非常大,遍历链表的时间复杂度为 $O(n)$,可能会影响系统性能。
### 代码示例
```c
int urlFilter_lru_cache_print(void) {
if ((NULL == lru_head.lru_htable) || (NULL == lru_head.lru_list) || list_empty(&lru_head.lru_list->node_list)) {
printk("LRU cache is empty, nothing to print\n");
return 0;
}
struct urlFilter_lru_node *node;
list_for_each_entry(node, &lru_head.lru_list->node_list, list) {
if (node->url != NULL) {
printk("URL: %s\n", node->url);
}
}
return 0;
}
```
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