Nor gate
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This document describes designing a NOR gate circuit using transistors, diodes, resistors, and switches to understand its working. The circuit consists of two input switches, two diodes, an LED, a transistor, resistors and a battery. It explains how current flows through the circuit depending on the input switch combinations, following the NOR gate truth table. The output is high only when both switches are released, and low in all other cases, demonstrating the NOR gate function.
Nor gate
- 1. Aim To understand the working of NOR gate using npn transistor, p-n junction diodes and to design a circuit of NOR gate using npn transistor, p-n junction diode, LED, push button type toggle switches and suitable resistances.
- 2. Introduction NOR gate is an Boolean operator based on the mathematical function of complement of addition. It works on digital signal as its input which have only two states of voltages, low as 0V and high as 5V. NOR gate consists of electonic circuit of two p-n junction diodes and npn transistor having two input digital signals which can take four different combinations on voltages, for each combination of voltages there is a predefined output according to complement of addition rule.
- 3. Apparatus used p-n junction diode (IN 4007) Npn transistor (547 b) Circuit board Wires 9V battery and battery connector LED (5mm, 1.5V) Resistors Push button type toggle switch Push buttons
- 4. Theory and working 1.)Working of p-n junction diode in forward and reverse biasing
- 6. 2.)Working of npn transistor in different configurations
- 7. 3.)Understanding the functioning of NAND gate
- 9. 4.)Circuit diagram used in making of NOR gate and its working When the push button is in ‘released state’ then terminal ‘2’ is connected to terminal ‘3’, when push button is in ‘active or pressed’ then terminal ‘2’ is connected to terminal ‘1’. The push button connected to first diode is ‘button 1’ and the other one is ‘button 2’. When ‘button 1’ is released and ‘button 2’ is released then it is equivalent to A(0), B(0). In this state, first diode is reverse biased and second diode is reverse biased, current does not flow through base of transistor, leading to cut-off
- 10. mode of transistor and current flows from collector to LED leading to high output. When ‘button 1’ is pressed and ‘button 2’ is released then it is equivalent to A(1), B(0). In this state, first diode is forward biased and second diode is reverse biased, current flows through base of transistor, leading to saturation mode of transistor and current flows from collector to negative terminal of battery through transistor, leading to no current through LED and low output. When ‘button 2’ is pressed and ‘button 1’ is released then it is equivalent to A(0), B(1). In this state, first diode is reverse biased and second diode is forward biased, current flows through base of transistor, leading to saturation mode of transistor and current flows from collector to negative terminal of battery through transistor, leading to no current through LED and low output. When ‘button 1’ is pressed and also ‘button 2’ is pressed then it is equivalent to A(1), B(1). In this state, first diode and second diode is reverse biased, current flows through base of transistor, leading to saturation mode of transistor and current flows from collector to negative terminal of battery through transistor, leading to no current through LED and low output.
- 11. Conclusion The output of NOR gate for different combinations inputs clearly shows the expected output according to the truth table. Sources of errors Write yourself Precautions Do not connect any electronic component without resistance in series, it can burn the component. Bibliography NCERT textbook of class 12 Physics by S.L.Arora Circuits available on internet