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Polar Equations
Polar EquationsPolars equations are equations in the variables r and .
Polar EquationsPolars equations are equations in the variables r and . Many curves may be described easier using relations in r and  rather than relations between x and y.
Polar EquationsPolars equations are equations in the variables r and . Many curves may be described easier using relations in r and  rather than relations between x and y.
Polar EquationsPolars equations are equations in the variables r and . Many curves may be described easier using relations in r and  rather than relations between x and y.
Polar EquationsThe Constant Equations r = c &  =c Frank Ma2006
Polar EquationsThe Constant Equations r = c &  =cI.   The equations r= c,
Polar EquationsThe Constant Equations r = c &  =cThe equation r = c, distance from the point to the origin = c, and  any number.
Polar EquationsThe Constant Equations r = c &  =cThe equation r = c, distance from the point to the origin = c, and  any number.	This equation describes the circle of radius c, centered at (0,0).  Frank Ma2006
Polar EquationsThe Constant Equations r = c &  =cThe equation r = c, distance from the point to the origin = c, and  any number.	This equation describes the circle of radius c, centered at (0,0).
Polar EquationsThe Constant Equations r = c &  =cII.   The equation  = c,
Polar EquationsThe Constant Equations r = c &  =cII.   The equation  = c, Directional angle to the point= c, and r any number.
Polar EquationsThe Constant Equations r = c &  =cII.   The equation  = c, Directional angle to the point= c, and r any number.	 This equation describes the line making the angle c to x-axis.
Polar EquationsThe Constant Equations r = c &  =cII.   The equation  = c, Directional angle to the point= c, and r any number.	 This equation describes the line making the angle c to x-axis.  r>0 Frank Ma2006=Cr<0
Polar Equationsr = ±c*cos() & r = ±c*sin()
Polar Equationsr = ±c*cos() & r = ±c*sin()The equations r = ±c*cos() r = ±c*sin()are circles.
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π Frank Ma2006
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              π
Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r             0             π½          7π/6      2/2      5π/43/2      4π/31           3π/23/2     5π/32/2     7π/4½        11π/60             2πr             0             0-½          π/6      -2/2      π/4-3/2      π/3-1           π/2-3/2    2π/3-2/2    3π/4-½        5π/60              πRemark: The graph consists of two circles as  goes from 0 to 2π
Polar Equationsr = ±c*cos() & r = ±c*sin()The graphs of r = ±c*cos() & r = ±c*sin()consists of two overlapping circles tangent to the axes at the origin as  goes from 0 to 2π.  r = c*sin()r = -c*cos()r = +c*cos()r = -c*sin()
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin() Frank Ma2006
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π Frank Ma2006
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π Frank Ma2006
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π Frank Ma2006
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π Frank Ma2006
Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r              1              π3/2          7π/6      1+2/2   5π/41+3/2   4π/32             3π/21+3/2   5π/31+2/2     7π/43/2         11π/61             2πr               1              0½             π/6      1-2/2      π/41-3/2      π/30               π/21-3/2      2π/31-2/2      3π/4½              5π/61                  π
Polar Equationsr = cos(n) & r = c*sin(n)
Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of : Frank Ma2006
Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of :1.  Find 0o <  < 360o where r=0
Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of :1.  Find 0o <  < 360o where r=02.  Find  between 0 and 360o where      |r| is greatest.
Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of :1.  Find 0o <  < 360o where r=02.  Find  between 0 and 360o where      |r| is greatest.3.  Trace the curves using 1 and 2.  Frank Ma2006
Polar EquationsExample: r = sin(2)
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2),
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720. Frank Ma2006
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2),
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225. Frank Ma2006
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1,  Frank Ma2006
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1, 2 = 270, 630,  = 135, 315
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1, 2 = 270, 630,  = 135, 31590Draw the directions that r = 0.18001270
Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1, 2 = 270, 630,  = 135, 3154590Draw the directions that r = 0.135Draw the directions that r = ±1. Frank Ma200618001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :4590135 Frank Ma200618001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 4590135 Frank Ma200618001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 4590135 Frank Ma200618001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. 459013518001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. 459013518001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. The similar observation  about the other two sectors gives us the complete graph.4590135 Frank Ma200618001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. The similar observation  about the other two sectors gives us the complete graph.459013518001225315270
Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. The similar observation  about the other two sectors gives us the complete graph.4590135This is known as the four-pedal-rose curve. Frank Ma200618001225315270
Equation Conversion
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form: Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin()r2 = x2 + y2, r = x2 + y2tan() = y/x  Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 into rectangular equation in x&y. Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 into rectangular equation in x&y.r = 3        square both sides
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 into rectangular equation in x&y.r = 3        square both sidesr2 = 9
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 into rectangular equation in x&y.r = 3        square both sidesr2 = 9       replace into x&y Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 into rectangular equation in x&y.r = 3        square both sidesr2 = 9       replace into x&yx2 + y2 = 9 Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos() Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2 = 3r – 3*r*cos()
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2 = 3r – 3*r*cos()     in x&y  Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2= 3r – 3*r*cos()    in x&y x2 + y2 = 3x2 + y2 – 3x
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2 = 3r – 3*r*cos()    in x&y x2 + y2 = 3x2 + y2 – 3x
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the rectangular equation 2x2 = 3x – 2y2 – 8  into polar equation.
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the rectangular equation 2x2 = 3x – 2y2 – 8  into polar equation.2x2 = 3x – 2y2 – 8 Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the rectangular equation 2x2 = 3x – 2y2 – 8  into polar equation.2x2 = 3x – 2y2 – 82x2 + 2y2 = 3x – 8  Frank Ma2006
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the rectangular equation 2x2 = 3x – 2y2 – 8  into polar equation.2x2 = 3x – 2y2 – 82x2 + 2y2 = 3x – 8 2(x2 + y2) = 3x – 8
Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example:  Convert the rectangular equation 2x2 = 3x – 2y2 – 8  into polar equation.2x2 = 3x – 2y2 – 82x2 + 2y2 = 3x – 8 2(x2 + y2) = 3x – 8 2r2 = 3rcos() – 8

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t7 polar equations and graphs

  • 2. Polar EquationsPolars equations are equations in the variables r and .
  • 3. Polar EquationsPolars equations are equations in the variables r and . Many curves may be described easier using relations in r and  rather than relations between x and y.
  • 4. Polar EquationsPolars equations are equations in the variables r and . Many curves may be described easier using relations in r and  rather than relations between x and y.
  • 5. Polar EquationsPolars equations are equations in the variables r and . Many curves may be described easier using relations in r and  rather than relations between x and y.
  • 6. Polar EquationsThe Constant Equations r = c &  =c Frank Ma2006
  • 7. Polar EquationsThe Constant Equations r = c &  =cI. The equations r= c,
  • 8. Polar EquationsThe Constant Equations r = c &  =cThe equation r = c, distance from the point to the origin = c, and  any number.
  • 9. Polar EquationsThe Constant Equations r = c &  =cThe equation r = c, distance from the point to the origin = c, and  any number. This equation describes the circle of radius c, centered at (0,0).  Frank Ma2006
  • 10. Polar EquationsThe Constant Equations r = c &  =cThe equation r = c, distance from the point to the origin = c, and  any number. This equation describes the circle of radius c, centered at (0,0).
  • 11. Polar EquationsThe Constant Equations r = c &  =cII. The equation  = c,
  • 12. Polar EquationsThe Constant Equations r = c &  =cII. The equation  = c, Directional angle to the point= c, and r any number.
  • 13. Polar EquationsThe Constant Equations r = c &  =cII. The equation  = c, Directional angle to the point= c, and r any number. This equation describes the line making the angle c to x-axis.
  • 14. Polar EquationsThe Constant Equations r = c &  =cII. The equation  = c, Directional angle to the point= c, and r any number. This equation describes the line making the angle c to x-axis. r>0 Frank Ma2006=Cr<0
  • 15. Polar Equationsr = ±c*cos() & r = ±c*sin()
  • 16. Polar Equationsr = ±c*cos() & r = ±c*sin()The equations r = ±c*cos() r = ±c*sin()are circles.
  • 17. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.
  • 18. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 19. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 20. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 21. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 22. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 23. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 24. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 25. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 26. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π Frank Ma2006
  • 27. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 28. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 29. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 30. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 31. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 32. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 33. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 34. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 35. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 36. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()The equations r = ±c*cos() r = ±c*sin()are circles.r 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 37. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 38. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 39. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 40. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 41. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 42. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 43. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 44. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 π
  • 45. Polar Equationsr = ±c*cos() & r = ±c*sin()Example: Graph r = -sin()r 0 π½ 7π/6 2/2 5π/43/2 4π/31 3π/23/2 5π/32/2 7π/4½ 11π/60 2πr 0 0-½ π/6 -2/2 π/4-3/2 π/3-1 π/2-3/2 2π/3-2/2 3π/4-½ 5π/60 πRemark: The graph consists of two circles as  goes from 0 to 2π
  • 46. Polar Equationsr = ±c*cos() & r = ±c*sin()The graphs of r = ±c*cos() & r = ±c*sin()consists of two overlapping circles tangent to the axes at the origin as  goes from 0 to 2π. r = c*sin()r = -c*cos()r = +c*cos()r = -c*sin()
  • 47. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin() Frank Ma2006
  • 48. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π
  • 49. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π
  • 50. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π Frank Ma2006
  • 51. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π Frank Ma2006
  • 52. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π
  • 53. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π
  • 54. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π
  • 55. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π Frank Ma2006
  • 56. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π Frank Ma2006
  • 57. Polar Equationsr = c(1 ± cos()) & r =c(1 ± sin())Example: Graph r = 1 – sin()r 1 π3/2 7π/6 1+2/2 5π/41+3/2 4π/32 3π/21+3/2 5π/31+2/2 7π/43/2 11π/61 2πr 1 0½ π/6 1-2/2 π/41-3/2 π/30 π/21-3/2 2π/31-2/2 3π/4½ 5π/61 π
  • 58. Polar Equationsr = cos(n) & r = c*sin(n)
  • 59. Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of : Frank Ma2006
  • 60. Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of :1. Find 0o <  < 360o where r=0
  • 61. Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of :1. Find 0o <  < 360o where r=02. Find  between 0 and 360o where |r| is greatest.
  • 62. Polar Equationsr = cos(n) & r = c*sin(n)The following steps help us to graph polar equations, especially equations made up with sine and cosine of :1. Find 0o <  < 360o where r=02. Find  between 0 and 360o where |r| is greatest.3. Trace the curves using 1 and 2.  Frank Ma2006
  • 64. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2),
  • 65. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720. Frank Ma2006
  • 66. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270
  • 67. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2),
  • 68. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225. Frank Ma2006
  • 69. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1,  Frank Ma2006
  • 70. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1, 2 = 270, 630,  = 135, 315
  • 71. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1, 2 = 270, 630,  = 135, 31590Draw the directions that r = 0.18001270
  • 72. Polar EquationsExample: r = sin(2) Find r = 0 = sin(2), 0 <  < 360 0 < 2 < 720.Therefore 2 = 0, 180, 360, 540, or  = 0, 90, 180, 270Find r = 1 = sin(2), 2 = 90, 450, or  = 45, 225.Find r = -1, 2 = 270, 630,  = 135, 3154590Draw the directions that r = 0.135Draw the directions that r = ±1. Frank Ma200618001225315270
  • 73. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :4590135 Frank Ma200618001225315270
  • 74. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 4590135 Frank Ma200618001225315270
  • 75. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 4590135 Frank Ma200618001225315270
  • 76. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. 459013518001225315270
  • 77. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. 459013518001225315270
  • 78. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. The similar observation about the other two sectors gives us the complete graph.4590135 Frank Ma200618001225315270
  • 79. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. The similar observation about the other two sectors gives us the complete graph.459013518001225315270
  • 80. Polar EquationsExample: r = sin(2) Investigate the graph in each sector from r = 0 to r = 0 :0 <  < 90  0 < 2 < 180, sin(2) goes from 0 to 1 back to 0. 90 <  <180  180 < 2 < 360, sin(2) goes from 0 to -1 to 0. The similar observation about the other two sectors gives us the complete graph.4590135This is known as the four-pedal-rose curve. Frank Ma200618001225315270
  • 82. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form: Frank Ma2006
  • 83. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin()r2 = x2 + y2, r = x2 + y2tan() = y/x  Frank Ma2006
  • 84. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 into rectangular equation in x&y. Frank Ma2006
  • 85. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 into rectangular equation in x&y.r = 3 square both sides
  • 86. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 into rectangular equation in x&y.r = 3 square both sidesr2 = 9
  • 87. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 into rectangular equation in x&y.r = 3 square both sidesr2 = 9 replace into x&y Frank Ma2006
  • 88. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 into rectangular equation in x&y.r = 3 square both sidesr2 = 9 replace into x&yx2 + y2 = 9 Frank Ma2006
  • 89. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.
  • 90. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos() Frank Ma2006
  • 91. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r
  • 92. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2 = 3r – 3*r*cos()
  • 93. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2 = 3r – 3*r*cos() in x&y  Frank Ma2006
  • 94. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2= 3r – 3*r*cos() in x&y x2 + y2 = 3x2 + y2 – 3x
  • 95. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the polar equation r = 3 – 3cos() into rectangular equation in x&y.r = 3 – 3cos(), multiply by r r2 = 3r – 3*r*cos() in x&y x2 + y2 = 3x2 + y2 – 3x
  • 96. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the rectangular equation 2x2 = 3x – 2y2 – 8 into polar equation.
  • 97. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the rectangular equation 2x2 = 3x – 2y2 – 8 into polar equation.2x2 = 3x – 2y2 – 8 Frank Ma2006
  • 98. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the rectangular equation 2x2 = 3x – 2y2 – 8 into polar equation.2x2 = 3x – 2y2 – 82x2 + 2y2 = 3x – 8  Frank Ma2006
  • 99. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the rectangular equation 2x2 = 3x – 2y2 – 8 into polar equation.2x2 = 3x – 2y2 – 82x2 + 2y2 = 3x – 8 2(x2 + y2) = 3x – 8
  • 100. Equation ConversionConversion Rule:To convert equations between the polar and rectangular form:x = r*cos()y = r*sin() r2 = x2 + y2tan() = y/x Example: Convert the rectangular equation 2x2 = 3x – 2y2 – 8 into polar equation.2x2 = 3x – 2y2 – 82x2 + 2y2 = 3x – 8 2(x2 + y2) = 3x – 8 2r2 = 3rcos() – 8