Arithmetic Mean, Geometric
Mean & Harmonic Mean
Dr. N. B. Vyas
Department of Science & Humanities
ATMIYA University
Arithmetic Mean
• If three numbers are in A.P. then the middle
number is said to be the Arithmetic Mean (AM)
of the first and the third numbers.
• E.g.
▫ 3,5,7 are in A.P. then 5 is A.M. of 3 & 7
▫ 10, 16, 22 are in A.P. then 16 is A.M. of 10 & 22
• If a and b are two numbers and if their A.M. is
denoted by A then a, A, b are in A.P.
• A= (a+b) / 2
Geometric Mean
• If three number are in G.P. then the middle
number is said to be Geometric Mean(G.M.) of
the first and third numbers.
• E.g.
▫ 1, 6, 36 are in GP then 6 is GM of 1 & 36
▫ 5, 10, 20 are in GP then 10 is GM of 5 & 20
• If a and b are two numbers and their G.M. is
denoted by G the a, G, b are in G.P.
abGabG 2
Q.1
• Find A.M. & G.M. of following numbmers:
1. 8 and 32
2. 2 and 18
3. 1/32 and 8
Q.2
• The AM and GM of two numbers are 25.5 and 12
respectively, find the numbers.
Q.3
• The AM of two numbers exceeds their positive
GM by 10 and the first number is 9 times the
second number, find the two numbers.
Q.4
• If three numbers 3, k+3 and 4k are in G.P. find
the value of k.
Q.5
• The sum of three numbers in AP is 30. If 2, 4
and 3 are deducted from them respectively the
resulting form G.P.
• Find the numbers
Q.6
• A person has to pay a debt of Rs.19600 in 40
monthly installments, which are in A.P. But after
paying 30 installments he dies, leaving Rs. 7,900
unpaid.
• Find the first installment paid by him.
Harmonic Progression
• A series x1, x2, x3,….,xn is said to be in Harmonic
Progression when their resicprocals 1/x1 , 1/x2 ,
1/x3 , … , 1/xn are in Arithmetic progression.
• Eg:
• ½ , ¼, 1/6 , 1/8, …
• 1/5 , 1/8 , 1/11 , 1/14 , …
• are in Harmonic Progression
• “if a, b, c are in H.P. then 1/a , 1/b , 1/c are in AP”
Harmonic Mean
• When three numbers are in H.P., the middle
number is called the Harmonic Mean between
the other two numbers.
• If a, H, b are in H.P. then H is the Harmonic
Mean of a and b.
• Also 1/a, 1/H, 1/b are in A.P.
• H = 2ab / (a+b)
Note:
• There is no general formula for the sum of any
number of terms in HP.
• Generally first we convert the given series into
AP and then use the properties of AP.
Ex
• Find the 29th term of the series
• ¼, 1/7, 1/11, 1/14,….
Solution:
• ¼, 1/7, 1/11, 1/14,…. are in HP
• Therefore, 4, 7, 11, 14, …. are in AP
• Here a=4, d=3
• Tn = a + (n-1) d
• For n = 29
• T29 = _____
• =88
• Therefore, 1/88 is the 29th term of HP.
Relation between AM, GM and HM
• For any two real numbers
• HM ≤ GM ≤ AM
• AM . HM
• = {(a+b) / 2 } . { 2ab / (a+b)}
• = ab
• = GM2
Ex
• Find HM of the following:
• (i) 2 and 32
• (ii) 8 and 18
• (iii) ½ and 8
Ex
• For two numbers 5 and 44, verify that
• (i) G2 = A. H
• (ii) H < G < A
Ex
• A person pays Rs.975 by monthly installments
each less than the former by Rs. 5.
• The first installment is Rs. 100
• In what time entire amount be paid?
Solution:
• There difference between two consecutive
installments is Rs. 5 i.e. constant, hence the
installments form an AP
• First installment = Rs. 100
• a =100, d = - 5 , Sn = 975

Arithmetic Mean, Geometric Mean, Harmonic Mean

  • 1.
    Arithmetic Mean, Geometric Mean& Harmonic Mean Dr. N. B. Vyas Department of Science & Humanities ATMIYA University
  • 2.
    Arithmetic Mean • Ifthree numbers are in A.P. then the middle number is said to be the Arithmetic Mean (AM) of the first and the third numbers. • E.g. ▫ 3,5,7 are in A.P. then 5 is A.M. of 3 & 7 ▫ 10, 16, 22 are in A.P. then 16 is A.M. of 10 & 22 • If a and b are two numbers and if their A.M. is denoted by A then a, A, b are in A.P. • A= (a+b) / 2
  • 3.
    Geometric Mean • Ifthree number are in G.P. then the middle number is said to be Geometric Mean(G.M.) of the first and third numbers. • E.g. ▫ 1, 6, 36 are in GP then 6 is GM of 1 & 36 ▫ 5, 10, 20 are in GP then 10 is GM of 5 & 20 • If a and b are two numbers and their G.M. is denoted by G the a, G, b are in G.P. abGabG 2
  • 4.
    Q.1 • Find A.M.& G.M. of following numbmers: 1. 8 and 32 2. 2 and 18 3. 1/32 and 8
  • 5.
    Q.2 • The AMand GM of two numbers are 25.5 and 12 respectively, find the numbers.
  • 6.
    Q.3 • The AMof two numbers exceeds their positive GM by 10 and the first number is 9 times the second number, find the two numbers.
  • 7.
    Q.4 • If threenumbers 3, k+3 and 4k are in G.P. find the value of k.
  • 8.
    Q.5 • The sumof three numbers in AP is 30. If 2, 4 and 3 are deducted from them respectively the resulting form G.P. • Find the numbers
  • 9.
    Q.6 • A personhas to pay a debt of Rs.19600 in 40 monthly installments, which are in A.P. But after paying 30 installments he dies, leaving Rs. 7,900 unpaid. • Find the first installment paid by him.
  • 10.
    Harmonic Progression • Aseries x1, x2, x3,….,xn is said to be in Harmonic Progression when their resicprocals 1/x1 , 1/x2 , 1/x3 , … , 1/xn are in Arithmetic progression. • Eg: • ½ , ¼, 1/6 , 1/8, … • 1/5 , 1/8 , 1/11 , 1/14 , … • are in Harmonic Progression • “if a, b, c are in H.P. then 1/a , 1/b , 1/c are in AP”
  • 11.
    Harmonic Mean • Whenthree numbers are in H.P., the middle number is called the Harmonic Mean between the other two numbers. • If a, H, b are in H.P. then H is the Harmonic Mean of a and b. • Also 1/a, 1/H, 1/b are in A.P. • H = 2ab / (a+b)
  • 12.
    Note: • There isno general formula for the sum of any number of terms in HP. • Generally first we convert the given series into AP and then use the properties of AP.
  • 13.
    Ex • Find the29th term of the series • ¼, 1/7, 1/11, 1/14,….
  • 14.
    Solution: • ¼, 1/7,1/11, 1/14,…. are in HP • Therefore, 4, 7, 11, 14, …. are in AP • Here a=4, d=3 • Tn = a + (n-1) d • For n = 29 • T29 = _____ • =88 • Therefore, 1/88 is the 29th term of HP.
  • 15.
    Relation between AM,GM and HM • For any two real numbers • HM ≤ GM ≤ AM • AM . HM • = {(a+b) / 2 } . { 2ab / (a+b)} • = ab • = GM2
  • 16.
    Ex • Find HMof the following: • (i) 2 and 32 • (ii) 8 and 18 • (iii) ½ and 8
  • 17.
    Ex • For twonumbers 5 and 44, verify that • (i) G2 = A. H • (ii) H < G < A
  • 18.
    Ex • A personpays Rs.975 by monthly installments each less than the former by Rs. 5. • The first installment is Rs. 100 • In what time entire amount be paid?
  • 19.
    Solution: • There differencebetween two consecutive installments is Rs. 5 i.e. constant, hence the installments form an AP • First installment = Rs. 100 • a =100, d = - 5 , Sn = 975