Dr. Brown has a radioactive source of 1.2 x 10^6 atoms of plutonium-238. In 352 years, due to the half-life of 87.7 years, approximately 74,292 atoms will remain. This calculation demonstrates the decay of radioactive materials over time.
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Dr. Brown has a radioactive source containing 1.2 x 106 (also writte.pdf
1. Dr. Brown has a radioactive source containing 1.2 x 106 (also written 1.2E+06) atoms of
Putonium -238 in 1985, how many atoms will remain in 352 years?
Solution
The half-life of Pu-238 is 87.7 years. In 352 years' time, this will mean that the number of atoms
left is 1.2 * 10^6 * (1/2)^(352/87.7)
That's 74292 atoms left, just about.