Eee316: Logical Instructions, Jump Commands, LOOPs and Arrays in Assembly Language
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The document describes an assembly language program that performs several tasks: 1) Finds the numbers divisible by 5 that lie between two given input numbers and stores them in an array. 2) Takes an input array, reverses the case of each element, and expresses any digits as their 10's complement value. 3) The code is debugged using different test values for the input numbers and array, and the results are displayed to check the program is working correctly.
![MOV AL, CL
ADD AL, DATA1
SUB AL, 1
MOV BL,DL
MOV [ARR+BX-1], AL
END_:
loop beginn
;
MOV ANS, DL
MOV AH, 4CH
INT 21H
;
ORG 1500H
DATA1 DB 22
ORG 1510H
DATA2 DB 39
ORG 1540H
ANS DB ?
ORG 1600H
ARR DB 80 DUP(0)
;
CODE ENDS
END
END MAIN
;how many numbers
;solution array
Debug Results:
In each debugging,
DATA1’s value is at 1410:1500.
DATA2’s value is at 1410:1510.
Answer ANS’s value is at 1410:1540.
Answer ARRAY is at 1410:1600.](https://image.slidesharecdn.com/eee316exp020304reportsubmittedby0906022-140125062906-phpapp02/85/Eee316-Logical-Instructions-Jump-Commands-LOOPs-and-Arrays-in-Assembly-Language-3-320.jpg)
![Lab Task:
Taking an input array and reversing the case of each
array-element; if any of them is digit, expressing that
as 10’s complement
Code:
CODE SEGMENT
ASSUME CS:CODE, DS:CODE
;
ORG 100H
;
MAIN: MOV AX, CS
MOV DS, AX
;
ORG 100H
ARR_ DB '1','A' ,'a','2','3','4','7','5','G','h','4','k';
ORG 1500H;
ANS DB 12 DUP(0);
MOV CX ,12;
MOV DL, 106;
LOOP1:
MOV BX,CX;
MOV AL,[ARR_+BX-1];
CMP AL,'9';
JG SKIP;
SUB DL,AL;
MOV AL, DL;
MOV DL,106;
MOV [ANS+BX-1],AL;
JMP EXIT_;
SKIP:
CMP AL,'Z';
JG SKIP1;
ADD AL,32;
MOV [ANS+BX-1],AL;
JMP EXIT_;
SKIP1:
SUB AL,32;
MOV [ANS+BX-1],AL;
;input array](https://image.slidesharecdn.com/eee316exp020304reportsubmittedby0906022-140125062906-phpapp02/85/Eee316-Logical-Instructions-Jump-Commands-LOOPs-and-Arrays-in-Assembly-Language-6-320.jpg)
Eee316: Logical Instructions, Jump Commands, LOOPs and Arrays in Assembly Language
- 1. Department of Electrical and Electronic Engineering Bangladesh University of Engineering and Technology Group No.: 05 Course No.: EEE 316 Course Name: Microprocessor Experiment No.: 02, and Interfacing Sessional. 03, 04 Experiment Name: Logical Instructions, Jump Commands, LOOPs and Arrays in Assembly Language Date of Performance: 21/01/2014 Date of Submission: 25/01/2014 Name: Musbiha Level: 3 Term: 2 Section: Binte Wali A1 Student No.: 0906022
- 2. Objective: To be familiar with the operations of Arrays in assembly language programming. Home Task: To write complete assembly language for the operation of finding out how many numbers divisible by 5 lie in between two given input numbers DATA1 and DATA2. Also finding out those numbers. Code: CODE SEGMENT ASSUME CS:CODE, DS:CODE ; ORG 100H ; MAIN: MOV AX, CS MOV DS, AX ; MOV BX, 0 MOV CX, 0 MOV DX, 0 MOV CL, DATA2 SUB CL, DATA1 ADD CL, 1 beginn: ;LOOP STARTS MOV AL, CL ADD AL, DATA1 SUB AL, 1 CBW ;AH will have the remainder MOV BL, 5 DIV BL CMP AH, 0 JZ AN_ JMP END_ AN_: ADD DL, 1 ;When Remainder is zero
- 3. MOV AL, CL ADD AL, DATA1 SUB AL, 1 MOV BL,DL MOV [ARR+BX-1], AL END_: loop beginn ; MOV ANS, DL MOV AH, 4CH INT 21H ; ORG 1500H DATA1 DB 22 ORG 1510H DATA2 DB 39 ORG 1540H ANS DB ? ORG 1600H ARR DB 80 DUP(0) ; CODE ENDS END END MAIN ;how many numbers ;solution array Debug Results: In each debugging, DATA1’s value is at 1410:1500. DATA2’s value is at 1410:1510. Answer ANS’s value is at 1410:1540. Answer ARRAY is at 1410:1600.
- 4. For DATA1= 2 and DATA2= 4, Answer=0 (at 1410:1540) and the Answer array contains no contents (at 1410:1600) For DATA1= 14 and DATA2= 16, Answer=01 (at 1410:1540) and the Answer array contains one content which is 15 (at 1410:1600)
- 5. For DATA1= 22 and DATA2= 39, Answer=03 (at 1410:1540) and the Answer array contains three contents which are 35, 30, 25 (at 1410:1600) For DATA1= 15 and DATA2= 50, Answer=08 (at 1410:1540) and the Answer array contains eight contents which are 50, 45, 40, 35, 30, 25, 20, 15 (at 1410:1600)
- 6. Lab Task: Taking an input array and reversing the case of each array-element; if any of them is digit, expressing that as 10’s complement Code: CODE SEGMENT ASSUME CS:CODE, DS:CODE ; ORG 100H ; MAIN: MOV AX, CS MOV DS, AX ; ORG 100H ARR_ DB '1','A' ,'a','2','3','4','7','5','G','h','4','k'; ORG 1500H; ANS DB 12 DUP(0); MOV CX ,12; MOV DL, 106; LOOP1: MOV BX,CX; MOV AL,[ARR_+BX-1]; CMP AL,'9'; JG SKIP; SUB DL,AL; MOV AL, DL; MOV DL,106; MOV [ANS+BX-1],AL; JMP EXIT_; SKIP: CMP AL,'Z'; JG SKIP1; ADD AL,32; MOV [ANS+BX-1],AL; JMP EXIT_; SKIP1: SUB AL,32; MOV [ANS+BX-1],AL; ;input array
- 7. EXIT_: LOOP LOOP1; MOV AH, 4CH INT 21H CODE ENDS END MAIN Result: In debugging window, Input array is at 1413:0200. Output array is at 1413:1500. Input array was: 1Aa23475Gh4k Output array is: 9aA87635gH6K