Engineering physics chapter 7 ch07-10e.ppt

Kinetic Energy and Work
Chapter 7
Copyright © 2014 John Wiley & Sons, Inc. All rights reserved.

7-1 Kinetic Energy
7.01 Apply the relationship
between a particle's kinetic
energy, mass, and speed.
7.02 Identify that kinetic energy
is a scalar quantity.
Learning Objectives
© 2014 John Wiley & Sons, Inc. All rights reserved.

7-1 Kinetic Energy
 Energy is required for any sort of motion
 Energy:
o Is a scalar quantity assigned to an object or a system of
objects
o Can be changed from one form to another
o Is conserved in a closed system, that is the total amount of
energy of all types is always the same
 In this chapter we discuss one type of energy (kinetic
energy)
 We also discuss one method of transferring energy
(work)

7-1 Kinetic Energy
 Kinetic energy:
o The faster an object moves, the greater its kinetic energy
o Kinetic energy is zero for a stationary object
 For an object with v well below the speed of light:
 The unit of kinetic energy is a joule (J)
Eq. (7-1)
Eq. (7-2)

7-1 Kinetic Energy
Example Energy released by 2 colliding trains with given
weight and acceleration from rest:
o Find the final velocity of each locomotive:
o Convert weight to mass:
o Find the kinetic energy:

7-2 Work and Kinetic Energy
between a force (magnitude
and direction) and the work
done on a particle by the
force when the particle
undergoes a displacement.
7.04 Calculate work by taking
a dot product of the force
vector and the displacement
vector, in either magnitude-
angle or unit-vector notation.
7.05 If multiple forces act on a
particle, calculate the net
work done by them.
7.06 Apply the work-kinetic
energy theorem to relate the
work done by a force (or the
net work done by multiple
forces) and the resulting
change in kinetic energy.
Learning Objectives

 Account for changes in kinetic energy by saying
energy has been transferred to or from the object
 In a transfer of energy via a force, work is:
o Done on the object by the force
 This is not the common meaning of the word “work”
o To do work on an object, energy must be transferred
o Throwing a baseball does work
o Pushing an immovable wall does not do work

 Start from force equation and 1-dimensional velocity:
 Rearrange into kinetic energies:
 The left side is now the change in energy
 Therefore work is:
Eq. (7-4)
Eq. (7-6)
Eq. (7-3)
Eq. (7-5)

 For an angle φ between force and displacement:
 As vectors we can write:
 Notes on these equations:
o Force is constant
o Object is particle-like (rigid)
o Work can be positive or negative
Eq. (7-8)
Eq. (7-7)

Figure 7-2
 Work has the SI unit of joules (J), the same as energy
 In the British system, the unit is foot-pound (ft lb)

 For two or more forces, the net work is the sum of the
works done by all the individual forces
 Two methods to calculate net work:
 We can find all the works and sum the individual work terms.
 We can take the vector sum of forces (Fnet) and calculate the
net work once

 The work-kinetic energy theorem states:
 (change in kinetic energy) = (the net work done)
 Or we can write it as:
 (final KE) = (initial KE) + (net work)
Eq. (7-10)
Eq. (7-11)

 The work-kinetic energy theorem holds for positive
and negative work
Example If the kinetic energy of a particle is initially 5 J:
o A net transfer of 2 J to the particle (positive work)
• Final KE = 7 J
o A net transfer of 2 J from the particle (negative work)
• Final KE = 3 J

Answer: (a) energy decreases (b) energy remains the same
(c) work is negative for (a), and work is zero for (b)

7-3 Work Done by the Gravitational Force
7.07 Calculate the work done
by the gravitational force
when an object is lifted or
lowered.
energy theorem to situations
where an object is lifted or
lowered.
Learning Objectives

 We calculate the work as we would for any force
 Our equation is:
 For a rising object:
 For a falling object:
Eq. (7-12)
Eq. (7-14)
Eq. (7-13)

 Work done in lifting or lowering an object, applying an
upwards force:
 For a stationary object:
o Kinetic energies are zero
o We find:
 In other words, for an applied lifting force:
 Applies regardless of path
Eq. (7-15)
Eq. (7-17)
Eq. (7-16)

 Figure 7-7 shows the
orientations of forces and their
associated works for upward
and downward displacement
 Note that the works (in 7-16)
need not be equal, they are only
equal if the initial and final
kinetic energies are equal
 If the works are unequal, you
will need to know the difference
between initial and final kinetic
energy to solve for the work
Figure 7-7

Figure 7-8
Examples You are a passenger:
o Being pulled up a ski-slope
• Tension does positive work, gravity does negative work

Examples You are a passenger:
o Being lowered down in an elevator
• Tension does negative work,
gravity does positive work
Figure 7-9

7-4 Work Done by a Spring Force
(Hooke's law) between spring
force, the stretch or
compression of the spring,
and the spring constant.
7.10 Identify that a spring force
is a variable force.
7.11 Calculate the work done
on an object by a spring
force by integrating the force
from the initial position to the
final position of the object or
by using the known generic
result of the integration.
7.12 Calculate work by
graphically integrating on a
graph of force versus
position of the object.
in which an object is moved
by a spring force.
Learning Objectives

 A spring force is the variable force from a spring
o A spring force has a particular mathematical form
o Many forces in nature have this form
 Figure (a) shows the spring in
its relaxed state: since it is
neither compressed nor
extended, no force is applied
 If we stretch or extend the
spring it resists, and exerts a
restoring force that attempts to
return the spring to its relaxed
state
Figure 7-10

 The spring force is given by Hooke's law:
 The negative sign represents that the force always
opposes the displacement
 The spring constant k is a is a measure of the
stiffness of the spring
 This is a variable force (function of position) and it
exhibits a linear relationship between F and d
 For a spring along the x-axis we can write:
Eq. (7-20)
Eq. (7-21)

 We can find the work by integrating:
 Plug kx in for Fx:
 The work:
o Can be positive or negative
o Depends on the net energy transfer
Eq. (7-23)
Eq. (7-25)

 For an initial position of x = 0:
 For an applied force where the initial and final kinetic
energies are zero:
Eq. (7-26)
Eq. (7-28)

Answer: (a) positive
(b) negative
(c) zero

7-5 Work Done by a General Variable Force
7.14 Given a variable force as
a function of position,
calculate the work done by it
on an object by integrating
the function from the initial to
the final position of the object
in one or more dimensions.
7.15 Given a graph of force
versus position, calculate the
work done by graphically
integrating from the initial
position to the final position
of the object.
7.16 Convert a graph of
acceleration versus position
to a graph of force versus
position.
where an object is moved by
a variable force.
Learning Objectives

 We take a one-dimensional
example
 We need to integrate the
work equation (which
normally applies only for a
constant force) over the
change in position
 We can show this process
by an approximation with
rectangles under the curve Figure 7-12

 Our sum of rectangles would be:
 As an integral this is:
 In three dimensions, we integrate each separately:
 The work-kinetic energy theorem still applies!
Eq. (7-31)
Eq. (7-32)
Eq. (7-36)

7-6 Power
between average power, the
work done by a force, and
the time interval in which that
work is done.
7.19 Given the work as a
function of time, find the
instantaneous power.
7.20 Determine the
instantaneous power by
taking a dot product of the
force vector and an object's
velocity vector, in magnitude-
angle and unit-vector
notations.
Learning Objectives

7-6 Power
 Power is the time rate at which a force does work
 A force does W work in a time Δt; the average power
due to the force is:
 The instantaneous power at a particular time is:
 The SI unit for power is the watt (W): 1 W = 1 J/s
 Therefore work-energy can be written as (power) x
(time) e.g. kWh, the kilowatt-hour
Eq. (7-42)
Eq. (7-43)

7-6 Power
 Solve for the instantaneous power using the definition
of work:
 Or:
Eq. (7-47)
Eq. (7-48)
Answer: zero (consider P = Fv cos ɸ, and note that ɸ = 90°)

Kinetic Energy
 The energy associated with
motion
Work
 Energy transferred to or from an
object via a force
 Can be positive or negative
7 Summary
Eq. (7-1)
Eq. (7-7)
Eq. (7-10)
Work Done by a Constant
Force
 The net work is the sum of
individual works
Work and Kinetic Energy
Eq. (7-11)
Eq. (7-8)

Work Done by the
Gravitational Force
Work Done in Lifting and
Lowering an Object
Eq. (7-16)
Eq. (7-26)
7 Summary
Eq. (7-12)
Spring Force
 Relaxed state: applies no force
 Spring constant k measures
stiffness
Eq. (7-20)
Spring Force
 For an initial position x = 0:

Work Done by a Variable
Force
 Found by integrating the
constant-force work equation
Power
 The rate at which a force does
work on an object
 Average power:
 Instantaneous power:
 For a force acting on a moving
object:
7 Summary
Eq. (7-32)
Eq. (7-43)
Eq. (7-47)
Eq. (7-42)
Eq. (7-48)

Problems
1. If a Saturn V rocket with an Apollo spacecraft attached had a combined
mass of 𝟐. 𝟗 × 𝟏𝟎𝟓 𝒌𝒈 and reached a speed of 11.2 km/s, how much kinetic
energy would it then have?
2. A father racing his son has half the kinetic energy of the son, who has half
the mass of the father. The father speeds up by 1.0 m/s and then has the
same kinetic energy as the son. What are the original speeds of (a) the
father and (b) the so

Problems

Problems
3. A 12.0 N force with a fixed orientation does work on a particle as the particle
moves through the three-dimensional displacement 𝑑 = (2𝑖 − 4𝑗 + 3𝑘) m.
What is the angle between the force and the displacement if the change in
the particle’s kinetic energy is (a) +30.0 J and (b) -30.0 J?

Problems
4. A 3.0 kg body is at rest on a frictionless horizontal air track when a constant
horizontal force acting in the positive direction of an x axis along the track is
applied to the body. A stroboscopic graph of the position of the body as it
slides to the right is shown in Fig. 7- 25.The force is applied to the body at 𝒕 =
𝟎, and the graph records the position of the body at 0.50 s intervals. How much
work is done on the body by the applied force 𝑭 between 𝒕 = 𝟎 𝒂𝒏𝒅 𝒕 = 𝟐 𝒔?

Problems
5. Figure 7-27 shows an overhead view of three horizontal forces acting on
a cargo canister that was initially stationary but now moves across a
frictionless floor. The force magnitudes are 𝑭𝟏= 𝟑𝑵, 𝑭𝟐 = 𝟒𝑵 𝒂𝒏𝒅 𝑭𝟑 =
𝟏𝟎𝑵and the indicated angles are 𝜽𝟐 = 𝟓𝟎° 𝒂𝒏𝒅𝜽𝟑 = 𝟑𝟓°. What is the net
work done on the canister by the three forces during the first 4 m of
displacement?

Engineering physics chapter 7 ch07-10e.ppt

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