F027037047

International Journal of Mathematics and Statistics Invention (IJMSI)
E-ISSN: 2321 – 4767 P-ISSN: 2321 - 4759
www.ijmsi.org Volume 2 Issue 7 || July. 2014 || PP-37-47
www.ijmsi.org 37 | P a g e
Two warehouses deteriorating items inventory model under partial backlogging, inflation and permissible delay in payments
Shital S. Patel
Department of Statistics, Veer Narmad South Gujarat University, Surat, INDIA ABSTRACT: A deteriorating items inventory model with two warehouses under time varying holding cost and linear demand with inflation and permissible delay in payments is developed. Shortages are allowed and partially backlogged. A rented warehouse (RW) is used to store the excess units over the capacity of the own warehouse. Numerical examples are provided to illustrate the model and sensitivity analysis is also carried out for parameters. KEYWORDS: Deterioration, Two-warehouse, Inventory, partial backlogging, Inflation, Permissible delay in payment
I. INTRODUCTION
In past few decays deteriorating items inventory models were widely studied. An inventory model with constant rate deterioration was developed by Ghare and Schrader [12]. The model was further extended by considering variable rate of deterioration by Covert and Philip [10]. Shah [30] further extended the model by considering shortages. The related work are found in (Nahmias [23], Raffat [25], Goyal and Giri [14], Mandal [21]), Mishra et al. [22]). The classical inventory model generally deal with single storage facility with the assumption that the available warehouse of the organization has unlimited capacity. But in actual practice, to take advantages of price discount for bulk purchases, a rented warehouse (RW) is used to store the excess units over the fixed capacity W of the own warehouse (OW). The cost of storing items at the RW is higher than that at the OW but provides better preserving facility with a lower rate of deterioration. Hartley [15] was the first one to consider a two warehouse model. A two warehouse deterministic inventory model with infinite rate of replenishment was developed by Sarma [29]. Pakkala and Achary [24] extended the two-warehouse inventory model for deteriorating items with finite rate of replenishment and shortages. Yang [31] considered a two warehouse inventory model for deteriorating items with constant rate of demand under inflation in two alternatives when shortages are completely backordered. Dye et al. [11] considered a two warehouse inventory model with partially backlogging. Jaggi et al. [16] developed an inventory model with linear trend in demand under inflationary conditions and partial backlogging rate in a two warehouse system.Related work is also find in (Benkherouf [3], Bhunia and Maiti [4], Kar et al. [19], Rong et al. [26], Sana et al. [28], Agarwal and Banerjee [1], Bhunia et al. [5]). Goyal [13] first considered the economic order quantity model under the condition of permissible delay in payments. Aggarwal and Jaggi [2] extended Goyal’s [13] model to consider the deteriorating items. Aggarwal and Jaggi’s [2] model was further extended by Jamal et al. [17] to consider shortages. The related work are found in (Chung and Dye [7], Jamal et al. [18], Salameh et al. [27], Chung et al. [8], Chang et al. [6]). Chung and Huang [9] proposed a two warehouse inventory model for deteriorating items under permissible delay in payments, but they assumed that the deterioration rate of the two warehouse were same. Liao and Huang [20] considered an order level inventory model for deteriorating items with two warehouse and a permissible delay in payments. In this paper we have developed a two-warehouse inventory model under time varying holding cost and linear demand with inflation and permissible delay in payments. Shortages are allowed and partially backlogged. Numerical examples are provided to illustrate the model and sensitivity analysis of the optimal solutions for major parameters is also carried out.

Two warehouses deteriorating Items inventory model…
II. ASSUMPTIONS AND NOTATIONS
NOTATIONS: The following notations are used for the development of the model: D(t) : Demand rate is a linear function of time t (a+bt, a>0, 0<b<1) A : Replenishment cost per order for two warehouse system c : Purchasing cost per unit p : Selling price per unit c2 : Shortage cost per unit c3 : Cost of lost sales per unit HC(OW): Holding cost per unit time is a linear function of time t (x1+y1t, x1>0, 0<y1<1) in OW HC(RW): Holding cost per unit time is a linear function of time t (x2+y2t, x2>0, 0<y2<1) in RW Ie : Interest earned per year Ip : Interest charged per year M : Permissible period of delay in settling the accounts with the supplier T : Length of inventory cycle I(t) : Inventory level at any instant of time t, 0 ≤ t ≤ T W : Capacity of owned warehouse I0(t) : Inventory level in OW at time t Ir(t) : Inventory level in RW at time t Q1 : Inventory level initially Q2 : Shortage of inventory Q : Order quantity R : Inflation rate tr : Time at which the inventory level reaches zero in RW in two warehouse system θ1t : Deterioration rate in OW, 0< θ1<1 θ2t : Deterioration rate in RW, 0< θ2<1 TCi : Total relevant cost per unit time (i=1,2,3) ASSUMPTIONS: The following assumptions are considered for the development of two warehouse model.
 The demand of the product is declining as a linear function of time.
 Replenishment rate is infinite and instantaneous.
 Lead time is zero.
 Shortages are allowed and partially backlogged.
 OW has a fixed capacity W units and the RW has unlimited capacity.
 The goods of OW are consumed only after consuming the goods kept in RW.
 The unit inventory costs per unit in the RW are higher than those in the OW.
 During the time, the account is not settled; generated sales revenue is deposited in an interest bearing account. At the end of the credit period, the account is settled as well as the buyer pays off all units sold and starts paying for the interest charges on the items in stocks.
III. THE MATHEMATICAL MODEL AND ANALYSIS
At time t=0, a lot size of certain units enter the system. W units are kept in OW and the rest is stored in RW. The items of OW are consumed only after consuming the goods kept in RW. In the interval [0,tr], the inventory in RW gradually decreases due to demand and deterioration and it reaches to zero at t=tr. In OW, however, the inventory W decreases during the interval [0,tr] due to deterioration only, but during [tr, t0], the inventory is depleted due to both demand and deterioration. By the time to t0, both warehouses are empty. Shortages occur during (t0,T) of size Q2 units. The figure describes the behaviour of inventory system.

Figure 1
. Hence, the inventory level at time t at RW and OW are governed by the following differential
equations:
r
2 r
dI (t)
+ θ tI (t) = - (a+bt),
dt
0  t  tr
(1)
with boundary conditions Ir(tr) = 0 and
0
1 0
dI (t)
+ θ tI (t) = 0,
dt
r 0  t  t
(2)
with initial condition I0(0) = W, respectively.
While during the interval (tr, t0), the inventory in OW reduces to zero due to the combined effect of
demand and deterioration both. So the inventory level at time t at OW, I0(t), is governed by the following
differential equation:
0
1 0
dI (t)
+ θ tI (t) = -(a+bt),
dt
r 0 t  t  t
(3)
with the boundary condition I0(t0)=0.
Similarly during (t0, T) the shortage level at time t, Is(t) is governed by the following differential equation:
s -δ(T - t) dI (t)
= - e (a+bt),
dt
t0≤t≤T, (4)
with the boundary condition Is(t0)=0.
The solutions to equations (1) to (4) are given by:
     
     
2 2 3 3
r r 2 r
r
4 4 2 2 2 2
2 r 2 r 2 r
1 1
a t - t + b t - t + aθ t - t
2 6
I (t) =
1 1 1
+ bθ t - t - aθ t t - t - bθ t t - t
8 2 4
 
 
 
 
 
r 0  t  t (5)
  2
o 1 I (t) = W 1 - θ t , r 0  t  t (6)
     
     
2 2 3 3
0 0 1 0
o
4 4 2 2 2 2
1 0 1 0 1 0
1 1
a t - t + b t - t + aθ t - t
2 6
I (t) =
1 1 1
+ bθ t - t - aθ t t - t - bθ t t - t
8 2 4
 
 
 
 
 
r 0 t  t  t (7)
3 2
s
3 2 2 2
0 0 0 0 0 0
1 1
- bδt - [aδ + b(1-δT)]t - at(1-δT)
3 2
I (t) =
1 1 1 1
+ bδt + aδt + bt - bδTt - aδt T + at
3 2 2 2
 
 
 
 
 
, t0≤t≤T
(8)
(by neglecting higher powers of θ1, θ2)
Using the condition Ir(t) = Q1 – W at t=0 in equation (5), we have

2 3 4
1 r r 2 r 2 r
1 1 1
Q - W = at + bt + aθ t + bθ t ,
2 6 8
 
 
 
2 3 4
1 r r 2 r 2 r
1 1 1
Q = W + at + bt + aθ t + bθ t .
2 6 8
 
  
 
(9)
Using the condition Is(t) = Q - Q1 at t=T in equation (8), we have
2 2
1 0 0
1
Q - Q = - a(T - t ) + b(T - t )
2
 
 
 
2 2
1 0 0
1
Q = Q - a(T - t ) + b(T - t ) .
2
 
  
 
(10)
Using the continuity of I0(t) at t=tr in equations (6) and (7), we have
 
     
     
2 2 3 3
0 r 0 r 1 0 r
2
o r 1
4 4 2 2 2 2
1 0 r 1 r 0 1 r 0 r
1 1
a t - t + b t - t + aθ t - t
2 6
I (t ) = W 1 - θ t =
1 1 1
+ bθ t - t - aθ t t - t - bθ t t - t
8 2 4
 
 
 
 
 
(11)
which implies that
2 2 2 2
1 r r r
0
- a + a + 2bW - bWθ t + b t + 2abt
t =
b
(12)
(by neglecting higher powers of tr and t0)
From equation (12), we note that t0 is a function of tr, therefore t0 is not a decision variable.
Based on the assumptions and descriptions of the model, the total annual relevant costs TCi, include the
following elements:
(i) Ordering cost (OC) = A
(13)
(ii)
tr
-Rt
2 2 r
0
HC(RW) =  (x +y t)I (t) e dt
     
     
r
2 2 3 3
t r r 2 r
-Rt
2 2
0 4 4 2 2 2 2
2 r 2 r 2 r
1 1
a t - t + b t - t + aθ t - t
2 6
= (x +y t) e dt
1 1 1
+ bθ t - t - aθ t t - t - bθ t t - t
8 2 4
 
 
 
 
 

   
 
7 6 2 5
2 2 r 2 2 2 2 2 r 2 2 2 2 2 2 2 r r r
2 4
2 2 2 2 2 r r 2 r
2 2
1 1 1 1 1 1 1 1 1 1
= - y Rθ bt + y -x R θ b- y Rθ a t + x θ b+ y -x R θ a-y R - θ bt +at - b t
56 6 8 3 5 8 3 2 2 2
1 1 1 1 1
+ x θ a + y -x R - θ bt + at - b + y Ra t
4 3 2 2 2
1 1 1
+ x - θ b
3 2 2
       
       
       
     
     
     
 
 
2 4 3 2 3
r r 2 2 2 2 r 2 r r r r
4 3 2 2 4 3 2
2 2 2 2 r 2 r r r r 2 2 r 2 r r r r
1 1 1 1
t + at - b - y -x R a - y R bθ t + aθ t + bt + at t
2 8 6 2
1 1 1 1 1 1 1
+ -x a + y -x R bθ t + aθ t + bt +at t + x bθ t + aθ t + bt +at t
2 8 6 2 8 6 2
       
       
       
     
     
     
(14)
(by neglecting higher powers of R)
(iii)
t0
-Rt
1 1 0
0
HC(OW) =  (x +y t)I (t) e dt
r 0
r
t t
-Rt -Rt
1 1 0 1 1 0
0 t
=  (x +y t)I (t)e dt +  (x +y t)I (t)e dt
 
tr
2 -Rt
1 1 1
0
=  (x +y t)W 1 - θ t e dt
     
     
0
r
2 2 3 3
t 0 0 1 0
-Rt
1 1
t 4 4 2 2 2 2
1 0 1 0 1 0
1 1
a t - t + b t - t + aθ t - t
2 6
+ (x +y t) e dt
1 1 1
+ bθ t - t - aθ t t - t - bθ t t - t
8 2 4
 
 
 
 
 


    5 4 3 2
1 1 r 1 1 1 r 1 1 1 0 1 1 0 1 r
1 1 1 1 1
= W y Rbθ t - y -x R θ t + - x θ - y R t + y -x R t x t
10 8 3 2 2
   
   
   
 
 
 
7 6
1 1 0 1 1 1 1 1 0
2 5
1 1 1 1 1 1 1 0 0 0
2 4
1 1 1 1 1 0 0 1 0
1
1 1 1 1
- y Rbθ t + y -x R bθ - y Raθ t
56 6 8 3
1 1 1 1 1 1
+ x bθ + y -x R aθ -y R - θ bt +at - b t
5 8 3 2 2 2
1 1 1 1 1
+ + x aθ + y -x R - θ bt +at - b y Ra t
4 3 2 2 2
1 1
+ x - θ
3 2
 
 
 
     
     
     
     
      
     
 
 
2 4 3 2 3
1 0 0 1 1 1 1 0 1 0 0 0 0
4 3 2 2 4 3 2
1 1 1 1 0 1 0 0 0 0 1 1 0 1 0 0 0 0
1 1 1 1 1
bt +at - b - y -x R a y R bθ t + aθ t + bt +at t
2 2 8 6 2
1 1 1 1 1 1 1
+ -x a - y -x R bθ t + aθ t + bt +at t + x bθ t + aθ t + bt +at t
2 8 6 2 8 6 2









        
         
        

      
      
      














 
 
 
7 6
1 1 r 1 1 1 1 1 r
2 5
1 1 1 1 1 1 1 0 0 r
2 4
1 1 1 1 1 0 0 1 r
1 1 1 1
y Rbθ t - y -x R bθ - y Raθ t
56 6 8 3
1 1 1 1 1 1
+ - x bθ + y -x R aθ - y R - θ bt +at - b t
5 8 3 2 2 2
1 1 1 1 1
- x aθ + y -x R - θ bt +at - b + y Ra t
4 3 2 2 2
   
  
  

      
            

      
      
      









 
 
2 4 3 2 3
1 1 0 0 1 1 1 1 0 1 0 0 0 r
4 3 2 2 4 3 2
1 1 1 1 0 1 0 0 0 r 1 1 0 1 0 0 0 r
1 1 1 1 1 1 1
- x - θ bt +at - b - y -x R a - y R bθ t aθ t bt +at t
3 2 2 2 8 6 2
+
1 1 1 1 1 1 1
- -x a + y -x R bθ t aθ t bt +at t - x bθ t aθ t bt +at t
2 8 6 2 8 6 2
        
          
        

     
         
      



 
 

(15)
(iv) Deterioration cost:
The amount of deterioration in both RW and OW during [0,t0] are:
tr
2 r
0
 θ tI (t)dt and
t0
1 0
0
 θ tI (t)dt
So deterioration cost
r 0 t t
-Rt -Rt
2 r 1 0
0 0
DC = c θ tI (t)e dt + θ tI (t)e dt
 
 
 
 
r r 0
r
t t t
-Rt -Rt -Rt
2 r 1 0 1 0
0 0 t
= c θ tI (t)e dt + θ tI (t)e dt + θ tI (t)e dt
 
 
 
  
7 6 2 5
2 r 2 2 r 2 2 r r r
2 4 4 3 2 3
2 2 r r r 2 r 2 r r r r
1 1 1 1 1 1 1 1 1
- Rθ bt + bθ - Raθ t + aθ -R - θ bt +at - b t
56 6 8 3 5 3 2 2 2
1 1 1 1 1 1 1 1
= cθ + - θ bt + at - b Ra t + -a - R bθ t + aθ t + bt + at t
4 2 2 2 3 8 6 2
+
       
       
       
       
        
       
4 3 2 2 5 4 3 2
2 r 2 r r r r 1 1 r 1 r r r
1 1 1 1 1 1 1 1
bθ t + aθ t + bt + at t + cθ W Rθ t - θ t - Rt + t
2 8 6 2 10 8 3 2
 
 
 
 
 
 
 
     
           
7 6 2 5
1 0 1 1 0 1 1 0 0 0
2 4 4 3 2 3
1 1 0 0 0 1 0 1 0 0 0 0
1 1 1 1 1 1 1 1 1
56 6 8 3 5 3 2 2 2
1 1 1 1 1 1 1 1
+ cθ + - θ bt + at - b Ra t + -a - R bθ t + aθ t + bt + at t
4 2 2 2 3 8 6 2
       
       
       
       
        
       
4 3 2 2
1 0 1 0 0 0 0
1 1 1 1
+ bθ t + aθ t + bt + at t
2 8 6 2
 
 
 
 
 
 
 
   
       

7 6 2 5
1 r 1 1 r 1 1 0 0 r
2 4 4 3 2
1 1 0 0 r 1 0 1 0 0 0 r
1 1 1 1 1 1 1 1 1
56 6 8 3 5 3 2 2 2
1 1 1 1 1 1 1 1
- cθ + - θ bt + at - b Ra t + -a - R bθ t + aθ t + bt + at t
4 2 2 2 3 8 6 2
       
       
       
       
        
       
3
4 3 2 2
1 0 1 0 0 0 r
1 1 1 1
+ bθ t + aθ t + bt + at t
2 8 6 2
 
 
 
 
 
 
 
   
       
(16)
(v) Shortage cost:
0
T
-Rt
2
t
SC = - c  I(t)e dt
0
3 2
T
-Rt
2
t 3 2 2 2
0 0 0 0 0 0
1 1
- bδt - [aδ + b(1-δT)]t - at(1-δT)
3 2
= - c e dt
1 1 1 1
+ bδt + aδt + bt - bδTt - aδt T + at
3 2 2 2
 
 
 
 
 

5 4
3
2
2 2 2 3 2
0 0 0 0 0 0
2 2
0 0
1 1 1 1 1
bδRT + - - aδ - b(1-δT) R - bδ T
15 4 2 2 3
1 1 1
+ a(1-δT)R - aδ - b(1-δT) T
3 2 2
= c
1 1 1 1 1
+ - aδt + bt - bδTt + bδt - aδTt + at R -a(1-δT) T
2 2 2 2 3
1 1
+ aδTt + bTt -
2 2
   
   
   
 
 
 
   
   
   
2 2 3 2
0 0 0 0
1 1
bδT t + bδTt - aδT t + aTt
2 3
 
 
 
 
 
 
 
 
 
 
 
 
5 4
0 0
3
0
2
2 2 2 3 2
0 0 0 0 0 0 0
3 3
0 0
1 1 1 1 1
bδRt + - - aδ - b(1-δT) R - bδ t
15 4 2 2 3
1 1 1
+ a(1-δT)R - aδ - b(1-δT) t
3 2 2
+ c
1 1 1 1 1
+ - aδt + bt - bδTt + bδt - aδTt + at R -a(1-δT) t
2 2 2 2 3
1 1
+ aδt + bt
2 2
   
   
   
 
 
 
   
   
   
3 4 2 2
0 0 0 0
.
1 1
- bδTt + bδt - aδTt + at
2 3
 
 
 
 
 
 
 
 
 
 
 
 
(17)
(vi) Cost due to lost sales:
LS =
2
T
-Rt
3
t
c  (a + bt)[1- (1 - δ(T - t)]e dt
2 2
0 0
3
3 3 4 4
0 2
1
aT(T - t ) + (bT - a -aRT)(T - t )
2
= cδ .
1 1
+ (- b -bRT + aR )(T - t ) + bR(T - t )
3 4
 
 
 
 
 
(18)
(vii) Interest Earned: There are two cases:
Case I : (M ≤ tr ≤ T):
In this case interest earned is:
 
M
-Rt
1 e
0
IE = pI  a + bt te dt   4 3 2
e
1 1 1
pI - bRM + - Ra + b M + aM
4 3 2
 
  
 
(19)
Case II : (t0 ≤ M ≤ T):
In this case interest earned is:
     
t0
-Rt
2 e 0 0 0
0
IE = pI a+bt te dt + a + bt t M - t
 
 
 
 

      2 3 2
e 0 0 0 0 0 0
1 1 1
= pI - bRt + - Ra + b t + at + a+bt t M-t
4 3 2
 
 
 
(20)
(viii) Interest Payable: There are three cases described as in figure:

Case I : (M ≤ tr ≤ T):
In this case, annual interest payable is:
r r 0
r
t t t
-Rt -Rt -Rt
1 p r 0 0
M M t
IP = cI I (t)e dt + I (t)e dt + I (t)e dt
 
 
 
  
6 5 2 4
2 r 2 2 r 2 2 r r r
2 3 4 3 2
p 2 r r r 2 r 2 r r r
1 1 1 1 1 1 1 1 1
- Rθ bt + θ b - Rθ a t + θ a - R - θ bt +at - b t
48 5 8 3 4 3 2 2 2
1 1 1 1 1 1 1 1
= cI + - θ bt +at - b+Ra t + - a - R bθ t + aθ t + bt +at
3 2 2 2 2 8 6 2
       
       
       
       
       
       
2
r
5 4 3 2
2 r 2 r r r
t
1 1 1
+ θ bt + aθ t + bt + at
8 6 2
 
 
 
 
 
 
 
 
 
 
6 5 2 4
2 2 2 2 2 r r
2 3 4 3 2 2
p 2 r r 2 r 2 r r r
1 1 1 1 1 1 1 1 1
- Rθ bM + θ b - Rθ a M + θ a - R - θ bt +at - b M
48 5 8 3 4 3 2 2 2
1 1 1 1 1 1 1 1
- cI + - θ bt +at - b+Ra M + - a - R bθ t + aθ t + bt +at M
3 2 2 2 2 8 6 2
+
       
       
       
       
       
       
4 3 2
2 r 2 r r r
1 1 1
θ bt M + aθ t M + bt M + at M
8 6 2
 
 
 
 
 
 
 
 
 
 
4 3 2 4 3 2
p r 1 r 1 r r p 1 1
1 1 1 1 1 1
+ cI W t + Rθ t - θ t - Rt - cI W M + Rθ M - θ M - RM
8 6 2 8 6 2
   
   
   
6 5 2 4
1 0 1 1 0 1 1 0 0 0
2 3 4 3 2
p 1 0 0 0 1 0 1 0 0 0
1 1 1 1 1 1 1 1 1
48 5 8 3 4 3 2 2 2
1 1 1 1 1 1 1 1
+ cI + - θ bt +at - b+Ra t + - a - R bθ t + aθ t + bt +at
3 2 2 2 2 8 6 2
       
       
       
       
       
       
2
0
5 4 3 2
1 0 1 0 0 0
t
1 1 1
8 6 2
 
 
 
 
 
 
 
 
 
 
6 5 2 4
1 r 1 1 r 1 1 0 0 r
2 3 4 3 2
p 1 0 0 r 1 0 1 0 0 0
1 1 1 1 1 1 1 1 1
48 5 8 3 4 3 2 2 2
1 1 1 1 1 1 1 1
- cI + - θ bt +at - b+Ra t + - a - R bθ t + aθ t + bt +at
3 2 2 2 2 8 6 2
       
       
       
       
       
       
2
r
4 3 2
1 0 r 1 0 r 0 r 0 r
t
1 1 1
+ θ bt t + aθ t t + bt t + at t
8 6 2
 
 
 
 
 
 
 
 
 
 
(21)
Case II : (tr ≤ M ≤ T):
In this case interest payable is:
t0
-Rt
2 p 0
M
IP = cI  I (t)e dt
6 5 2 4
1 0 1 1 0 1 1 0 0 0
2 3 4 3 2
p 1 0 0 0 1 0 1 0 0
1 1 1 1 1 1 1 1 1
48 5 8 3 4 3 2 2 2
1 1 1 1 1 1 1 1
= cI + - θ bt +at - b+Ra t + - a - R bθ t + aθ t + bt +aT t
3 2 2 2 2 8 6 2
       
       
       
       
       
       
2
0
5 4 3 2
1 0 1 0 0 0
1 1 1
8 6 2
 
 
 
 
 
 
 
 
 
 

6 5 2 4
1 1 1 1 1 0 0
2 3 4 3 2 2
p 1 0 0 1 0 1 0 0 0
1 1 1 1 1 1 1 1 1
- Rθ bM + θ b - Rθ a M + θ a - R - θ bt +at - b M
48 5 8 3 4 3 2 2 2
1 1 1 1 1 1 1 1
- cI + - θ bt +at - b+Ra M + - a - R bθ t + aθ t + bt +at M
3 2 2 2 2 8 6 2
+
       
       
       
       
       
       
4 3 2
1 0 1 0 0 0
1 1 1
θ bt M + aθ t M + bt M + at M
8 6 2
 
 
 
 
 
 
 
 
 
 
(22)
Case III : (t0 ≤ M ≤ T):
In this case, no interest charges are paid for the item. So,
IP3 = 0. (23)
The retailer’s total cost during a cycle, TCi(tr,T), i=1,2,3 consisted of the following:
  i i i
1
TC = A + HC(OW) + HC(RW) + DC+ SC + LS + IP - IE
T
(24)
and t0 is approximately related to tr through equation (12).
Substituting values from equations (13) to (18) and equations (19) to (23) in equation (24), total costs for the
three cases will be as under:
  1 1 1
1
T
(25)
  2 2 1
1
T
(26)
  3 3 2
1
T
(27)
The optimal value of tr = tr*, T=T* (say), which minimizes TCi can be obtained by solving equation (25), (26)
and (27) by differentiating it with respect to tr and T and equate it to zero i.e.
i.e. i r i r
r
TC (t ,T) TC (t ,T)
= 0, = 0,
t T
 
 
i=1,2,3, (28)
provided it satisfies the condition
2 2
i r i r
2 2
r
C (t ,T) C (t ,T)
>0, >0
t T
 
 
and
2
2 2 2
i r i r i r
2 2
r r
C (t ,T) C (t ,T) C (t ,T)
- > 0, i=1,2,3.
t T t T
     
     
         
(29)
IV. NUMERICAL EXAMPLES
Case I: Considering A= Rs.150, W = 100, a = 200, b=0.05, c=Rs. 10, p= Rs. 15, θ1=0.1, θ2 =0.06, x1 = Rs. 1,
y1=0.05, x2= Rs. 3, y2=0.06, Ip= Rs. 0.15, Ie= Rs. 0.12, R = 0.06, c2 = Rs. 8, c3 = Rs. 2, δ = 0.8, M=0.01 year, in
appropriate units. The optimal value of
*
r t =0.0831, T*=0.8081 and
*
1 TC = Rs. 349.8128.
Case II: Considering A= Rs.150, W = 100, a = 200, b=0.05, c = Rs. 10, p= Rs. 15, θ1=0.1, θ2 =0.06, x1= Rs. 1,
y1=0.05, x2= Rs. 3, y2=0.06, Ip= Rs. 0.15, Ie = Rs. 0.12, c2 = Rs. 8, c3 = Rs. 2, δ = 0.8, M=0.55 year, in
*
r t =0.0867, T*=0.7151 and
*
2 TC = Rs. 215.9081.
Case III: Considering A= Rs.150, W = 100, a = 200, b=0.05, c = Rs. 10, p= Rs. 15, θ1=0.1, θ2 =0.06, x1= Rs. 1,
y1=0.05, x2= Rs. 3, y2=0.06, Ip= Rs. 0.15, Ie= Rs. 0.12, c2 = Rs. 8, c3 = Rs. 2, δ = 0.8, M = 0.65 year, in
*
r t =0.1014, T*=0.7101 and
*
1 TC = Rs. 185.5066.
The second order conditions given in equation (29) are also satisfied. The graphical representation of
the convexity of the cost functions for the three cases are also given.
Case I
tr and cost T and cost tr, T and cost

Graph 1 Graph 2 Graph 3
Case II
tr and cost
T and cost
tr, T and cost Graph 4 Graph 5 Graph 6
Case III
tr and cost
T and cost
tr, T and cost Graph 7 Graph 8 Graph 9
V. SENSITIVITY ANALYSIS
On the basis of the data given in example above we have studied the sensitivity analysis by changing the following parameters one at a time and keeping the rest fixed.
Case I
Case II
Case III
(M ≤ tr ≤ T)
(tr ≤ M ≤ T)
(t0 ≤ M ≤ T)
Para- meter
%
tr
T
Cost
tr
T
Cost
tr
T
Cost
a
+10%
0.0951
0.7620
367.8316
0.1068
0.6783
218.6641
0.1149
0.6672
185.5466
+5%
0.0895
0.7841
358.9034
0.0973
0.6959
217.3366
0.1086
0.6878
185.5075
-5%
0.0758
0.8344
340.5512
0.0749
0.7362
214.3719
0.0932
0.7345
185.3120
-10%
0.0674
0.8633
331.1092
0.0616
0.7596
212.7207
0.0838
0.7613
184.9143
x1
+10%
0.0774
0.8055
353.8748
0.0830
0.7144
220.5564
0.0969
0.7087
190.3883
+5%
0.0802
0.8068
351.8509
0.0848
0.7148
218.2381
0.0991
0.7094
187.9540
-5%
0.0860
0.8094
347.7605
0.0885
0.7154
213.5663
0.1036
0.7108
183.0461
-10%
0.0888
0.8107
345.6942
0.0904
0.7157
211.2129
0.1058
0.7115
180.5725
x2
+10%
0.0786
0.8037
350.0558
0.0833
0.7119
216.2113
0.0965
0.7054
185.9206

+5% 0.0808 0.8059 349.9375 0.0850 0.7134 216.0626 0.0989 0.7077 185.7184
-5% 0.0856 0.8105 349.6812 0.0885 0.7168 215.7475 0.1040 0.7127 185.2846
-10% 0.0882 0.8131 349.5419 0.0904 0.7186 215.5806 0.1068 0.7153 185.0514
θ1
+10% 0.0806 0.8062 350.6601 0.0850 0.7140 216.8554 0.0991 0.7085 186.5307
+5% 0.0819 0.8072 350.2374 0.0858 0.7145 216.3824 0.1003 0.7093 186.0197
-5% 0.0844 0.8091 349.3862 0.0876 0.7157 215.4322 0.1025 0.7109 184.9916
-10% 0.0857 0.8101 348.9576 0.0885 0.7162 214.9549 0.1037 0.7118 184.4746
θ2
+10% 0.0831 0.8081 349.8143 0.0867 0.7151 215.9099 0.1013 0.7101 185.5096
+5% 0.0831 0.8081 349.8135 0.0867 0.7151 215.9090 0.1014 0.7101 185.5081
-5% 0.0831 0.8082 349.8121 0.0867 0.7151 215.9071 0.1014 0.7102 185.5051
-10% 0.0832 0.8082 349.8114 0.0867 0.7151 215.9062 0.1014 0.7102 185.5037
δ
+10% 0.0835 0.8083 350.2002 0.0869 0.7141 216.1404 0.1016 0.7092 185.6874
+5% 0.0833 0.8082 350.0065 0.0868 0.7146 216.0246 0.1015 0.7097 185.5973
-5% 0.0829 0.8081 349.6190 0.0866 0.7156 215.7909 0.1013 0.7106 185.4152
-10% 0.0827 0.8080 349.4251 0.0865 0.7160 215.6730 0.1012 0.7111 185.3232
R
+10% 0.0836 0.8098 349.4392 0.0865 0.7156 215.9521 0.1011 0.7104 185.5842
+5% 0.0834 0.8090 349.6263 0.0866 0.7153 215.9302 0.1013 0.7103 185.5455
-5% 0.0829 0.8073 349.9988 0.0868 0.7149 215.8857 0.1015 0.7100 185.4675
-10% 0.0826 0.8065 350.1843 0.0869 0.7146 215.8630 0.1017 0.7098 185.4282
A
+10% 0.0832 0.8080 349.5957 0.1004 0.7179 199.1456 0.1044 0.7005 165.5004
+5% 0.0832 0.8081 349.7043 0.0935 0.7164 207.4508 0.1029 0.7053 175.5502
-5% 0.0831 0.8082 349.9214 0.0800 0.7141 224.5186 0.0998 0.7148 195.3707
-10% 0.0830 0.8082 350.0298 0.0734 0.7133 233.2833 0.0981 0.7195 205.1433
M
+10% 0.1018 0.8418 367.9956 0.1017 0.7440 236.4685 0.1205 0.7427 206.1560
+5% 0.0926 0.8251 358.9970 0.0943 0.7297 226.2903 0.1110 0.7266 195.9471
-5% 0.0735 0.7910 340.4325 0.0789 0.7003 205.3104 0.0915 0.6934 174.8192
-10% 0.0636 0.7735 332.2985 0.0710 0.6853 194.4848 0.0814 0.6763 163.8678
From the table we observe that as parameter a increases/ decreases average total cost increases/
decreases in case I and case II and there is very slight increase/ decrease in case III with respective increase/
decrease in parameter a..
From the table we observe that with increase/ decrease in parameters x1 and θ1, there is corresponding increase/
decrease in total cost for case I, case II and case III respectively.
Also, we observe that with increase and decrease in the value of x2, θ2, δ and R, there is corresponding
very slight increase/ decrease in total cost for case I, case II and case III. From the table we observe that with
increase/ decrease in M, there is corresponding decrease/ increase in total cost for case I, case II and case III
respectively. Moreover, we observe that with increase/ decrease in the value of A, there is corresponding
increase/ decrease in total cost in cases I, II and III.
VI. CONCLUSION
We have developed a two warehouse inventory model for deteriorating items with linear demand and
partial backlogging under inflationary conditions and permissible delay in payments in this model. It is assumed
that rented warehouse holding cost is greater than own warehouse holding cost but provides a better storage
facility and there by deterioration rate is low in rented warehouse. Sensitivity with respect to parameters have
been carried out. The results show that there is increase/ decrease in cost when there is increase/ decrease in the
parameter values.
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