Individuals that express the disease sickle cell anemia are homozygo.pdf
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The document discusses sickle cell anemia, indicating that individuals with the disease are homozygous for a recessive allele. It provides calculations based on Hardy-Weinberg equilibrium (HWE) to determine the frequency of the recessive allele (q=0.05), the frequency of carriers (0.095), and the probability of two carriers mating (0.9025%).
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Individuals that express the disease sickle cell anemia are homozygo.pdf
- 1. Individuals that express the disease sickle cell anemia are homozygous for a recessive allele for a hemoglobin gene. The frequency of individuals expressing the disease in a particular population is 0.0025. If we assume that the population is at HWE, what is the frequency of the recessive sickle cell allele? If the population is at HWE, what is the expected frequency of carriers of the disease (heterozygotes)? If mating is random, what is the probability that two carriers will mate? *University of Washington Solution q2 = .0025 q=.0025=0.05 (p+q=1) (q=1-0.05=0.95) If we assume that the population is at HWE, what is the frequency of the recessive sickle cell allele? The frequency of the recessive sickle cell allele, q=0.05 If the population is at HWE, what is the expected frequency of carriers of the disease (heterozygotes)? Expected frequency of carriers of the disease=2pq= 2*0.05*0.95=0.095 If mating is random, what is the probability that two carriers will mate? The probability that two carriers will mate =0.095*0.095=9.025x10-3 or 9.025x10-3 x100=0.9025%