Interview Mocha's Score Distribution Analysis
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The document discusses using score distribution analysis to help recruiters quickly evaluate how well candidates fit a role. It describes calculating the mean, standard deviation, and bell curve of scores to analyze where candidates fall relative to the average. A low standard deviation means scores are close to the average, while a high value means more variation. An example calculates the mean of 76 and standard deviation of 14.53 for 5 candidates' test scores to benchmark them against the average.
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Interview Mocha's Score Distribution Analysis
- 2. Why is the score distribution analysis done? › Recruiters shouldn’t have to flip between the job description and a candidate’s score report to identify how well the candidate fits the role. › At a glance, a recruiter should be able to quickly identify if a candidate’s score falls within the “acceptable fit or average” zone of the scale. Ergo, Mocha’s score distribution analysis does the job!
- 3. Identify the candidate amongst average score via › Standard Deviation › Mean › Bell Curve
- 4. Standard Deviation (SD) SD is used to indicate how many candidates are spread out in relation to the average(mean) score. › A low SD value close to 0, indicates candidates close to average score. › A high SD value is spread out, away from the average score.
- 5. View the percentage of candidates in the range close to the average value (here: 0)
- 6. Using the standard deviation formula, we can calculate high and low SD values Sum of Mean Number of candidates
- 7. Example Candidates Test scores James 92 Lilian 88 Victor 80 Jordon 68 Jamie 52 › Test – General Aptitude › Appeared candidates - 5 › Test score - 100
- 8. 1. Find the mean: (92+88+80+68+52)/5 = 76 Mean (x) = 76 2. Find the deviation from the mean: 92-76 = 16 88-76 = 12 80-76 = 04 68-76 = -8 52-76 = -24
- 9. 3. Square the deviation from the mean: (16)^2 = 256 (12)^2 = 144 (04)^2 = 16 (-8)^2 = 64 (-24)^2 = 576 4. Find the sum of the squares of the deviation from the mean: 256+144+16+64+576 = 1056
- 10. 5. Divide the number of total candidates to find the variance: 1056/5 = 211.2 6. Find the square root of the variance: Thus the Standard deviation of the test score is 14.53 and mean is 76
- 11. Therefore, to Benchmark the candidate with respect to the average score, we display the analysis in the form of a Bell curve. The standard deviation slots will be in the range of 14.53 above and below the mean/average score of 76. e.g. A candidate named Greg scoring 65 will be seen among 68% of the bulk scoring close to the average marks.
- 12. THANK YOU!