Measuring
Interpupillary Distance
Optom.Askar.P K
Aoptoaskar.p
Anatomic pupillary distance
Distance from centre of one pupil to the centre of the
other pupil
Measured in millimeters(mm)
Sharma IP,
Why to measureIPD?
Sharma IP,
Instruments for measuringPD
Sharma IP,
 P D ruler
Rodenstock Interpupillary gauge
Pupillometer (Elissor pupillometer)
Topcon Digital PD meter, Model PD 5
 C a l coast PD ruler
Instruments for measuringPD
Cal coast PD Meter Digital Essilor Pupillometer
PD ruler
Sharma IP,
We can usethis
Sharma IP,
Binocular Distance IPD
Sharma IP,
 A : Between center of two pupil
 B : Right temporal pupillary margin to left nasal
pupillary margin
C:Right temporal limbus to left nasal limbus
Sharma IP,
Technique
Sharma IP,
Steps in Measuring binocular distance PD using a ruler
1.Dispenser position at 40 cm(16inches)
2.Dispenser closes right eye , patient fixes at dispensers open left eye
3.Dispenser lines up the ruler zero point on the subject’s right pupil, left pupillary
border or left limbus.
4. Dispenser closes left eye , patient fixes at dispensers open right eye
5.Dispenser reads scale directly in line with subject’s left pupil center ,left pupillary
border or left limbus
6.Dispenser closes right eye, opens left; subject fixates on dispenser’s left eye
7.Dispenser checks to make sure that zero point is still correct
Common difficulties andtheir
solution
Sharma IP,
Problem Solution
1.Dispenser cannot close one eye Occlude the eye with free hand
2.Subject is strabismic Cover the subjects eye not been
observed
3.Subject is uncooperative child Take a canthus- canthus
measurement
Monocular DistanceIPD
Sharma IP,
Technique
Sharma IP,
Steps in Measuring monocular distance PD using a ruler
1.Measure the binocular PD using center of pupil as reference point
2.Before moving the ruler, note the reading at the center of the nose. This is
the monocular PD of oneeye
3.Stbtract this reading from the binocular reading to obtain the reading of
the other eye.
Near PD
Sharma IP,
Near PD
Sharma IP,
 Required for single vision reading glasses or for
multifocal lenses
 C a n be either measured or calculated
Technique
Sharma IP,
Steps in Measuring near PD using a ruler
1.Dispenser places his/her dominant eye in front of the subject’s nose at the
subjects near working distance
2.Dispenser close the non-dominant eye
3.Subject fixates on dispenser’s open eye.
4.Dispenser places zero point of the PD ruler at the center of subject’s right
pupil.
5.Scale reading at the center of the subject’s left eye is read.
Calculating near PD
Sharma IP,
 M o s t commonly usedis called three -quarter rule
 I t states that “for every diopter of dioptric demand, the
optical center of each reading lens, or the geometrical
center of each bifocal addition, should be insert
0.75(three-quarters) mm.”
Dioptric demand=inverse of reading distance in
meters
and is independent of actual bifocal addition power
Example
Sharma IP,
 A spectacle lens wearer has the following
prescription:
OD: -1.00 DS
OS: -1.00 DS
Add: +2.00DS
Distance PD is 64mm.
What is the near PD at 40 cm?
Solution:
Sharma IP,
Dioptric demand=1/0.40 =2.50 D
Insert per lens =2.50 x (3/4) =1.9mm
= 2.00mm (approx)
We need to deduct 2 mm from each lens i.e 4 mm from the distance IPD
Near IPD= 64mm- 64 mm
=60mm
Easiest Solution: Deduct 4 mm from distance PD for normal
working distance
Orthoptics as a career (ZG)

IPD Measurement

  • 1.
  • 2.
    Anatomic pupillary distance Distancefrom centre of one pupil to the centre of the other pupil Measured in millimeters(mm) Sharma IP,
  • 3.
  • 4.
    Instruments for measuringPD SharmaIP,  P D ruler Rodenstock Interpupillary gauge Pupillometer (Elissor pupillometer) Topcon Digital PD meter, Model PD 5  C a l coast PD ruler
  • 5.
    Instruments for measuringPD Calcoast PD Meter Digital Essilor Pupillometer PD ruler Sharma IP,
  • 6.
  • 7.
  • 8.
     A :Between center of two pupil  B : Right temporal pupillary margin to left nasal pupillary margin C:Right temporal limbus to left nasal limbus Sharma IP,
  • 9.
    Technique Sharma IP, Steps inMeasuring binocular distance PD using a ruler 1.Dispenser position at 40 cm(16inches) 2.Dispenser closes right eye , patient fixes at dispensers open left eye 3.Dispenser lines up the ruler zero point on the subject’s right pupil, left pupillary border or left limbus. 4. Dispenser closes left eye , patient fixes at dispensers open right eye 5.Dispenser reads scale directly in line with subject’s left pupil center ,left pupillary border or left limbus 6.Dispenser closes right eye, opens left; subject fixates on dispenser’s left eye 7.Dispenser checks to make sure that zero point is still correct
  • 10.
    Common difficulties andtheir solution SharmaIP, Problem Solution 1.Dispenser cannot close one eye Occlude the eye with free hand 2.Subject is strabismic Cover the subjects eye not been observed 3.Subject is uncooperative child Take a canthus- canthus measurement
  • 11.
  • 12.
    Technique Sharma IP, Steps inMeasuring monocular distance PD using a ruler 1.Measure the binocular PD using center of pupil as reference point 2.Before moving the ruler, note the reading at the center of the nose. This is the monocular PD of oneeye 3.Stbtract this reading from the binocular reading to obtain the reading of the other eye.
  • 13.
  • 14.
    Near PD Sharma IP, Required for single vision reading glasses or for multifocal lenses  C a n be either measured or calculated
  • 15.
    Technique Sharma IP, Steps inMeasuring near PD using a ruler 1.Dispenser places his/her dominant eye in front of the subject’s nose at the subjects near working distance 2.Dispenser close the non-dominant eye 3.Subject fixates on dispenser’s open eye. 4.Dispenser places zero point of the PD ruler at the center of subject’s right pupil. 5.Scale reading at the center of the subject’s left eye is read.
  • 16.
    Calculating near PD SharmaIP,  M o s t commonly usedis called three -quarter rule  I t states that “for every diopter of dioptric demand, the optical center of each reading lens, or the geometrical center of each bifocal addition, should be insert 0.75(three-quarters) mm.” Dioptric demand=inverse of reading distance in meters and is independent of actual bifocal addition power
  • 17.
    Example Sharma IP,  Aspectacle lens wearer has the following prescription: OD: -1.00 DS OS: -1.00 DS Add: +2.00DS Distance PD is 64mm. What is the near PD at 40 cm?
  • 18.
    Solution: Sharma IP, Dioptric demand=1/0.40=2.50 D Insert per lens =2.50 x (3/4) =1.9mm = 2.00mm (approx) We need to deduct 2 mm from each lens i.e 4 mm from the distance IPD Near IPD= 64mm- 64 mm =60mm Easiest Solution: Deduct 4 mm from distance PD for normal working distance
  • 19.
    Orthoptics as acareer (ZG)