Lambdas and Streams Master Class Part 2

#Devoxx
Java Lambda Stream
Master Class – Part 2
@StuartMarks @JosePaumard

#LambdaHOL#Devoxx
Stuart Marks
JDK Core Libraries Developer
Java Plaform Group, Oracle
Twitter: @stuartmarks

#LambdaHOL#Devoxx
@JosePaumard
https://www.youtube.com/user/JPaumard
https://www.slideshare.net/jpaumard
https://github.com/JosePaumard

#Devoxx #LambdaHOL
Questions?
#LambdaHOL

#LambdaHOL#Devoxx
Lambda/Streams Master Class 2
Setup
Map, Filter, FlatMap
Reduction, Function combination
Collectors.toMap()
Collectors.groupingBy()
Cascading Collectors
Streaming a Map
Streaming over Indexes

#LambdaHOL#Devoxx
Back to the Comparator
How to deal with null names?
Comparator<Person> cmp = Comparator.comparing(Person::getLastName)
.thenComparing(Person::getFirstName)
.thenComparing(Person::getAge);

#LambdaHOL#Devoxx
In fact, this comparator:
Is equivalent to this one:
Comparator.comparing(Person::getLastName)
Comparator.comparing(Person::getLastName, Comparator.naturalOrder())

#LambdaHOL#Devoxx
This allows this pattern:
So, to deal with null values:
Comparator.comparing(Person::getLastName,
Comparator.nullsLast(Comparator.naturalOrder()))
Comparator.comparing(String::length))

#LambdaHOL#Devoxx
If we need to deal with null Person objects and
null names:
Comparator.nullsLast(
Comparator.nullsLast(Comparator.naturalOrder())
)
)

#LambdaHOL#Devoxx
The LambdaHOL
You can find it here
https://github.com/stuart-marks/LambdaHOLv2
https://github.com/JosePaumard/lambda-master-class-part2

#LambdaHOL#Devoxx
Input Data — Alphabet
List<String> alphabet = List.of(
"alfa", "bravo", "charlie", "delta", "echo",
"foxtrot", "golf", "hotel", "india", "juliet",
"kilo", "lima", "mike", "november", "oscar",
"papa", "quebec", "romeo", "sierra", "tango",
"uniform", "victor", "whiskey", "x-ray", "yankee", "zulu");

#LambdaHOL#Devoxx
Input Data — Sonnet
List<String> sonnet = List.of(
"From fairest creatures we desire increase,",
"That thereby beauty's rose might never die,",
"But as the riper should by time decease,",
"His tender heir might bear his memory:",
"But thou contracted to thine own bright eyes,",
"Feed'st thy light's flame with self-substantial fuel,",
"Making a famine where abundance lies,",
"Thy self thy foe, to thy sweet self too cruel:",
"Thou that art now the world's fresh ornament,",
"And only herald to the gaudy spring,",
"Within thine own bud buriest thy content,",
"And, tender churl, mak'st waste in niggarding:",
"Pity the world, or else this glutton be,",
"To eat the world's due, by the grave and thee.");

#LambdaHOL#Devoxx
Helper Method — expand()
expand("abc") ⇒ ["a", "b", "c"]
List<String> expand(String s) {
return s.codePoints()
.mapToObj(Character::toString)
.collect(toList());
}

#Devoxx #LambdaHOL
Map, Filter using Streams

#LambdaHOL#Devoxx
Map, Filter Example
• From the Alphabet list
• Map to upper case
• Only keep the words with 6 letters

#LambdaHOL#Devoxx
Map, Filter Example
alphabet.stream()
.map(String::toUpperCase)
.filter(word -> word.length() == 6)
.forEach(System.out::println);
JULIET
QUEBEC
SIERRA
VICTOR
YANKEE

#LambdaHOL#Devoxx
FlatMap
• Intermediate stream operation
• Consumes one element
• May produce zero or more elements
• Compare to map: consumes one, produces
one
• How is zero-or-more represented? A stream!
• T ⇒ Stream<R>

#LambdaHOL#Devoxx
FlatMap
Given a list of strings...
[alfa, bravo, charlie, ...]
expand each string to a list of one-letter strings
[ [a, l, f, a], [b, r, a, v, o], [c, h, ...] ... ]
but «flatten» the nesting structure
[a, l, f, a, b, r, a, v, o, c, h, ...]

#LambdaHOL#Devoxx
FlatMap
[[a, l, f, a], [b, r, a, v, o], [c, h, ...] ...]
List<List<String>> flatMap1() {
return alphabet.stream()
.map(word -> expand(word))
.collect(toList());
}

#LambdaHOL#Devoxx
FlatMap
[a, l, f, a, b, r, a, v, o, c, h, a, r, l, i, e, d, e, l, ...]
List<String> flatMap2() {
.flatMap(word -> expand(word).stream())
.collect(toList());
}

#LambdaHOL#Devoxx
FlatMap — Exercise
Split each line of the sonnet into words, and
then collect all the words into a single list.
To split a line into words, use
line.split(" +")
note: this returns an array, not a list or stream

#LambdaHOL#Devoxx
FlatMap — Solution
Split each line of the sonnet into words, and then
collect all the words into a single list.
[From, fairest, creatures, we, desire, increase, ...]
total 106 words
List<String> flatMapSolution() {
return sonnet.stream()
.flatMap(line -> Arrays.stream(line.split(" +")))
.collect(toList());
}

#LambdaHOL#Devoxx
Computing Factorials
Compute the factorial as a BigInteger using
streams and reduction
long number = 21;
// result is 51_090_942_171_709_440_000

#LambdaHOL#Devoxx
Computing Factorials
Compute the factorial as a BigInteger using
streams and reduction
long number = 21;
BigInteger result = LongStream.rangeClosed(1, 21)
.mapToObj(BigInteger::valueOf)
.reduce(BigInteger.ONE, BigInteger::multiply);
// result is 51_090_942_171_709_440_000

#Devoxx #LambdaHOL
Function Combination

#LambdaHOL#Devoxx
Suppose you have a shopping website where
the customer can apply a filter to limit the
products shown.
List<Product> show(Predicate<Product> predicate) {
return getAllProducts().stream()
.filter(predicate)
.collect(toList());
}

#LambdaHOL#Devoxx
Suppose you want the customer to be able to
apply two filters to the product list.
Now, how about three filters?
List<Product> show(Predicate<Product> p1, Predicate<Product> p2) {
.filter(p1.and(p2))
.collect(toList());
}

#LambdaHOL#Devoxx
Two predicates can be combined using the
Predicate.and() method.
This is all we need to write a method that
combines an arbitrary number of predicates.
Predicate<Product> p1 = ... ;
Predicate<Product> p2 = ... ;
Predicate<Product> combined = p1.and(p2);

#LambdaHOL#Devoxx
Reduction of a list over an operator applies that
operator between each element.
Predicate<Product> combine(List<Predicate<Product>> predicates) {
Predicate<Product> temp = product -> true;
for (Predicate<Product> cur : predicates) {
temp = temp.and(cur);
}
return temp;
}

#LambdaHOL#Devoxx
Reduction of a list over an operator applies that
operator between each element.
Predicate<Product> combine(List<Predicate<Product>> predicates) {
return predicates.stream()
.reduce(product -> true, Predicate::and);
}

#LambdaHOL#Devoxx
Now apply this to the original problem:
List<Product> show(List<Predicate<Product>> predicates) {
Predicate<Product> combinedPredicate = combine(predicates);
.filter(combinedPredicate)
.collect(toList());
}

#LambdaHOL#Devoxx
Function Combination — Exercise
An IntUnaryOperator is a functional interface that
takes an int and returns an int.
Write a method that combines an arbitrary sized
list of IntUnaryOperators into a single one.
Use streams and the IntUnaryOperator.andThen()
method.
Use your method to combine functions that add
one, multiply by two, and three.

#LambdaHOL#Devoxx
Function Combination — Exercise
IntUnaryOperator combine(List<IntUnaryOperator> operators) {
// TODO
}
IntUnaryOperator operator =
combine(List.of(i -> i + 1, i -> i * 2, i -> i + 3));
System.out.println(operator.applyAsInt(5));
15

#LambdaHOL#Devoxx
Function Combination — Solution
IntUnaryOperator combine(List<IntUnaryOperator> operators) {
return operators.stream()
.reduce(i -> i, IntUnaryOperator::andThen);
}
IntUnaryOperator operator =
combine(List.of(i -> i + 1, i -> i * 2, i -> i + 3));
System.out.println(operator.applyAsInt(5));
15

#Devoxx #LambdaHOL
Collectors.toMap()

#LambdaHOL#Devoxx
Collectors.toMap()
Collectors.toMap(keyFunction, valueFunction)
Takes each stream element
▪ runs the keyFunction to get a key
▪ runs the valueFunction to get a value
▪ enters computed (key, value) entries into the
result map
Returns the map as the final result

#LambdaHOL#Devoxx
Collectors.toMap()
Given the alphabet words, create a map whose
keys are the first letter and whose values are
the words.
Map<String, String> toMap1() {
.collect(toMap(word -> word.substring(0, 1),
word -> word));
}

#LambdaHOL#Devoxx
Collectors.toMap()
a => alfa
b => bravo
c => charlie
d => delta
e => echo
f => foxtrot
g => golf
h => hotel
i => india
j => juliet
k => kilo
l => lima
m => mike
n => november
o => oscar

#LambdaHOL#Devoxx
Collectors.toMap()
Now create the first-letter map using the
sonnet instead of the alphabet words.
.collect(toMap(word -> word.substring(0, 1),
word -> word));
}

#LambdaHOL#Devoxx
Collectors.toMap()
Exception in thread "main" java.lang.IllegalStateException: Duplicate key B (attempted merging values
But as the riper should by time decease, and But thou contracted to thine own bright eyes,)
at java.base/java.util.stream.Collectors.duplicateKeyException(Collectors.java:133)
at java.base/java.util.stream.Collectors.lambda$uniqKeysMapAccumulator$1(Collectors.java:180)
at java.base/java.util.stream.ReduceOps$3ReducingSink.accept(ReduceOps.java:169)
at java.base/java.util.AbstractList$RandomAccessSpliterator.forEachRemaining(AbstractList.java:720)

#LambdaHOL#Devoxx
Collectors.toMap()
The simple (two-arg) toMap() requires that all
keys be unique. Throws exception if duplicate
keys are encountered.
To handle this, a third arg mergeFunction can be
provided. It takes the values of the duplicate
keys and returns a merged value.

#LambdaHOL#Devoxx
Collectors.toMap()
Use a merge function that simply returns its
first argument. “First wins.”
.collect(toMap(line -> line.substring(0, 1),
line -> line,
(line1, line2) -> line1 // merge
));
}

#LambdaHOL#Devoxx
Collectors.toMap()
Eight of fourteen lines remain, so some
duplicates were lost.
P => Pity the world, or else this glutton be,
A => And only herald to the gaudy spring,
B => But as the riper should by time decease,
T => That thereby beauty's rose might never die,
F => From fairest creatures we desire increase,
W => Within thine own bud buriest thy content,
H => His tender heir might bear his memory:
M => Making a famine where abundance lies,

#LambdaHOL#Devoxx
Collectors.toMap()
Use a “last wins” merge function.
.collect(toMap(line -> line.substring(0, 1),
line -> line,
(line1, line2) -> line2 // merge
));
}

#LambdaHOL#Devoxx
Collectors.toMap()
Eight entries, but some are different.
A => And, tender churl, mak'st waste in niggarding:
B => But thou contracted to thine own bright eyes,
T => To eat the world's due, by the grave and thee.
F => Feed'st thy light's flame with self-substantial fuel,

#LambdaHOL#Devoxx
Collectors.toMap() — Exercise
Create a map from the lines of the sonnet, with
map keys being the first letter of the line, and
values being the line. For duplicate keys,
concatenate the lines with a newline in
between.

#LambdaHOL#Devoxx
Collectors.toMap() — Solution
Map<String, String> toMapSolution() {
.collect(
toMap(line -> line.substring(0, 1),
line -> line,
(line1, line2) ->
line1 + System.lineSeparator() + line2));
}

#LambdaHOL#Devoxx
Collectors.toMap() — Solution
And, tender churl, mak'st waste in niggarding:
But thou contracted to thine own bright eyes,
Thy self thy foe, to thy sweet self too cruel:
Thou that art now the world's fresh ornament,
To eat the world's due, by the grave and thee.
Feed'st thy light's flame with self-substantial fuel,

#Devoxx #LambdaHOL
Collectors.groupingBy

#LambdaHOL#Devoxx
The groupingBy() collector is a fancy way of
collecting a map from a stream.
In its simplest form, it takes a classifier function
to transform each stream element into a key.
Map values are a list of stream elements
classified into the same key.
Stream<T> ⇒ Map<K, List<V>>

#LambdaHOL#Devoxx
From the alphabet words, create a map whose
keys are the word length, and whose values are
a list of those words. First start off with toMap().
Map<Integer, List<String>> groupingBy1() {
.collect(
toMap(
word -> word.length(),
word -> new ArrayList<>(Arrays.asList(word)),
(list1, list2) -> { list1.addAll(list2);
return list1; }));
}

#LambdaHOL#Devoxx
4 => [alfa, echo, golf, kilo, lima, mike, papa, zulu]
5 => [bravo, delta, hotel, india, oscar, romeo, tango, x-ray]
6 => [juliet, quebec, sierra, victor, yankee]
7 => [charlie, foxtrot, uniform, whiskey]
8 => [november]

#LambdaHOL#Devoxx
Change toMap() to groupingBy(). Same result!
.collect(toMap(String::length,
s -> new ArrayList<>(Arrays.asList(s)),
(a, b) -> { a.addAll(b); return a; }));
}
.collect(groupingBy(String::length));
}

#LambdaHOL#Devoxx
Collectors.groupingBy() — Exercise
Collect the lines of the sonnet into a map,
whose keys are the first letter of each line, and
whose values are a list of lines beginning with
that letter.

#LambdaHOL#Devoxx
Collectors.groupingBy() — Solution
Map<String, List<String>> groupingBySolution() {
.collect(groupingBy(line -> line.substring(0, 1)));
}

#LambdaHOL#Devoxx
Collectors.groupingBy() — Solution
P => [Pity the world, or else this glutton be,]
A => [And only herald to the gaudy spring,,
And, tender churl, mak'st waste in niggarding:]
B => [But as the riper should by time decease,,
But thou contracted to thine own bright eyes,]
T => [That thereby beauty's rose might never die,,
Thy self thy foe, to thy sweet self too cruel:,
Thou that art now the world's fresh ornament,,
To eat the world's due, by the grave and thee.]
F => [From fairest creatures we desire increase,,
Feed'st thy light's flame with self-substantial fuel,]
W => [Within thine own bud buriest thy content,]
H => [His tender heir might bear his memory:]
M => [Making a famine where abundance lies,]

#Devoxx #LambdaHOL

#LambdaHOL#Devoxx
The groupingBy() collector seems restrictive: it
collects stream elements into a list.
This behavior can be modified by providing a
“downstream” collector as another argument.
groupingBy(classifier, downstream)

#LambdaHOL#Devoxx
Collectors.counting()
A useful downstream collector is counting()
The counting() collector is analogous to
Stream.count().

#LambdaHOL#Devoxx
The pattern is the following:
Map<String, Long> cascading2() {
.collect(groupingBy(line -> line.substring(0, 1),
Collectors.counting()));
}

#LambdaHOL#Devoxx
P => 1L
A => 2L
B => 2L
T => 4L
F => 2L
W => 1L
H => 1L
M => 1L

#LambdaHOL#Devoxx
Collectors.mapping()
Another useful downstream collector is
mapping():
mapping(mapperFunction, downstream2)
The mapping() collector is analogous to
Stream.map(). It applies a mapper function to
an element and passes the result downstream
— to a second downstream collector.

#LambdaHOL#Devoxx
These are equivalent:
Map<String, List<String>> cascading2() {
.collect(
groupingBy(
line -> line.substring(0, 1),
mapping(line -> line, toList())
));
}
Map<String, List<String>> cascading1() {
.collect(groupingBy(line -> line.substring(0, 1)));
}

#LambdaHOL#Devoxx
The using mapping() as the downstream
collector enables:
▪ the stream elements collected into map values
can be transformed
▪ the transformed elements can be collected or
reduced differently

#LambdaHOL#Devoxx
Map<String, List<Integer>> cascading3() {
.collect(
groupingBy(
mapping(String::length, toList())
));
} P => [40]
A => [36, 46]
B => [40, 45]
T => [43, 46, 45, 46]
F => [42, 53]
W => [41]
H => [38]
M => [37]

#LambdaHOL#Devoxx
Cascading Collectors — Exercise
Group the lines of the sonnet by first letter, and
collect the first word of grouped lines into a set.
To extract the first word of a line, use
string.split(" +")[0]

#LambdaHOL#Devoxx
Cascading Collectors — Solution
Map<String, Set<Integer>> cascading3() {
.collect(
groupingBy(
mapping(line -> line.split(" +")[0], toSet())
));
} P => [Pity]
A => [And, And,]
B => [But]
T => [That, Thy, To, Thou]
F => [Feed'st, From]
W => [Within]
H => [His]
M => [Making]

#LambdaHOL#Devoxx
A first set of collectors that need downstream
collectors to work:
- mapping()
- filtering()
- flatMapping()
Analogous to intermediate stream operations

#LambdaHOL#Devoxx
A second set of collectors:
▪ joining()
▪ counting()
▪ groupingBy(), toMap(), toUnmodifiableMap()
▪ toList(), toSet(), toUnmodifiableList() (and set)
▪ reducing()
Analogous to terminal stream operations

#LambdaHOL#Devoxx
Group lines of the sonnet by first letter, and
collect the grouped lines into a single string
separated by newlines.
Map<String, String> cascading4() {
.collect(groupingBy(line -> line.substring(0, 1),
joining("n")
)
);
}

#LambdaHOL#Devoxx
And, tender churl, mak'st waste in niggarding:
But thou contracted to thine own bright eyes,
Thy self thy foe, to thy sweet self too cruel:
Thou that art now the world's fresh ornament,
To eat the world's due, by the grave and thee.
Feed'st thy light's flame with self-substantial fuel,

#LambdaHOL#Devoxx
Cascading Collectors — Exercise
Generate a frequency table of letters in the
sonnet. Remember the expand() helper
method.
Hints: use flatMap(), groupingBy(), and
counting().

#LambdaHOL#Devoxx
Cascading Collectors — Solution
Map<String, Long> cascadingSolution2() {
.flatMap(line -> expand(line).stream())
.collect(groupingBy(ch -> ch, counting()));
}
A => 2
B => 2
F => 2
H => 1
M => 1
P => 1
T => 4
W => 1
=> 92
a => 28
b => 11
c => 9
d => 20
e => 68
f => 9
g => 12
' => 6
h => 33
i => 29
k => 2
l => 18
, => 15
- => 1
m => 10
. => 1
n => 29
o => 25
p => 2
r => 33
s => 30
t => 54
u => 17
v => 2
w => 11
y => 14
: => 3

#Devoxx #LambdaHOL
Streaming a Map

#LambdaHOL#Devoxx
Streaming a Map
Find the most frequently occurring word from
the Sonnet
- 1st step: find one of those words
- 2nd step: find all those words in a list

#LambdaHOL#Devoxx
Streaming a Map
Two hints:
1) You cannot stream a map. To stream a map,
you need to get a stream of entries from its
entrySet().
Stream<Map.Entry<K, V>> stream =
map.entrySet().stream();

#LambdaHOL#Devoxx
Streaming a Map
Two hints:
2) There is a Stream.max() method
And Map.Entry provides comparators
stream.max(comparator)
.orElseThrow(); // max returns an Optional
stream.max(Map.Entry.comparingByValue())
.orElseThrow(); // max returns an Optional

#LambdaHOL#Devoxx
Inverting a Map
Suppose there are multiple maximum values
Max finds one of them
Finding all of them can be done by
converting a Map<word, count>
to a Map<count, List<word>>

#Devoxx #LambdaHOL
Streaming Over Indexes

#LambdaHOL#Devoxx
Sometimes you need to process groups of
adjacent elements or a “sliding window” of
elements from a stream. The usual way of
streaming elements doesn’t handle this well.
If you have the elements in an array or random-
access list, you can work around this limitation
by streaming indexes instead of elements.

#LambdaHOL#Devoxx
Split into sublists of size N adjacent elements:
N=3:
List<List<String>> streamIndexes1(int N) {
int SIZE = alphabet.size();
return IntStream.range(0, SIZE/N)
.mapToObj(i -> alphabet.subList(N*i, N*(i+1)))
.collect(toList());
}
[[alfa, bravo, charlie], [delta, echo, foxtrot], [golf, hotel, india],
[juliet, kilo, lima], [mike, november, oscar], [papa, quebec, romeo],
[sierra, tango, uniform], [victor, whiskey, x-ray]]

#LambdaHOL#Devoxx
Adjust ranges and protect bounds with min():
return IntStream.range(0, (SIZE+N-1)/N)
.mapToObj(i -> alphabet.subList(N*i, Math.min(SIZE, N*(i+1))))
.collect(toList());
}
[sierra, tango, uniform], [victor, whiskey, x-ray], [yankee, zulu]]

#LambdaHOL#Devoxx
Alternatively, use rangeClosed():
return IntStream.rangeClosed(0, (SIZE+N-1)/N)
.mapToObj(i -> alphabet.subList(N*i, Math.min(SIZE, N*(i+1))))
.collect(toList());
}
[sierra, tango, uniform], [victor, whiskey, x-ray], [yankee, zulu]]

#LambdaHOL#Devoxx
Streaming Over Indexes — Exercise
From the alphabet list, produce a list of
overlapping sublists of length N (sliding
window)
[[alfa, bravo, charlie], [bravo, charlie, delta], [charlie, delta,
echo], [delta, echo, foxtrot], [echo, foxtrot, golf], ...

#LambdaHOL#Devoxx
Streaming Over Indexes — Solution
One solution:
List<List<String>> streamIndexesSolution1(int N) {
return IntStream.range(0, SIZE-N+1)
.mapToObj(i -> alphabet.subList(i, i+N))
.collect(toList());
}

#LambdaHOL#Devoxx
Streaming Over Indexes — Solution
Variation:
List<List<String>> streamIndexesSolution2(int N) {
return IntStream.rangeClosed(N, SIZE)
.mapToObj(i -> alphabet.subList(i-N, i))
.collect(toList());
}

#LambdaHOL#Devoxx
Streaming Over Indexes — Exercise 2
Split the alphabet list into runs (sublists) of
strings of non-decreasing length, preserving
order.
That is, within each sublist, the next string
should always be the same length or longer.
[[alfa, bravo, charlie], [delta], [echo, foxtrot], [golf, ...] ...]

#LambdaHOL#Devoxx
Streaming Over Indexes — Solution 2
Insight: a new sublist starts when this string is
shorter than the previous string. Find the
indexes where this occurs.
[3, 4, 6, 10, 14, 15, 17, 19, 21, 23, 25]
List<Integer> breaks =
IntStream.range(1, alphabet.size())
.filter(i -> alphabet.get(i).length() <
alphabet.get(i-1).length())
.boxed()
.collect(toList());

#LambdaHOL#Devoxx
We want sublists between these breaks. Run a
stream over the breaks to generate sublists.
[[delta], [echo, foxtrot], [golf, hotel, india, juliet], [kilo, lima,
mike, november], [oscar], [papa, quebec], [romeo, sierra], [tango,
uniform], [victor, whiskey], [x-ray, yankee]]
List<List<String>> sublists =
IntStream.range(0, breaks.size()-1)
.mapToObj(i -> alphabet.subList(breaks.get(i),
breaks.get(i+1)))
.collect(toList());

#LambdaHOL#Devoxx
Add starting and ending indexes to break list to
pick up leading and trailing sublists.
[[alfa, bravo, charlie], [delta], [echo, foxtrot], [golf, hotel, india,
juliet], [kilo, lima, mike, november], [oscar], [papa, quebec], [romeo,
sierra], [tango, uniform], [victor, whiskey], [x-ray, yankee], [zulu]]
breaks.add(0, 0);
breaks.add(alphabet.size());
breaks.get(i+1)))
.collect(toList());

#LambdaHOL#Devoxx
List<Integer> breaks =
IntStream.range(1, alphabet.size())
.filter(i -> alphabet.get(i).length() <
alphabet.get(i-1).length())
.boxed()
.collect(toList());
breaks.add(0, 0);
breaks.add(alphabet.size());
breaks.get(i+1)))
.collect(toList());

#LambdaHOL#Devoxx
[[alfa, bravo, charlie], [delta], [echo, foxtrot], [golf, hotel, india,
juliet], [kilo, lima, mike, november], [oscar], [papa, quebec], [romeo,
sierra], [tango, uniform], [victor, whiskey], [x-ray, yankee], [zulu]]

#Devoxx
Questions?
@StuartMarks @JosePaumard
#LambdaHOL

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