Length and Area
Year 7 Maths
Measurements
Limits of accuracy
• The accuracy of a measurement is how
close that measurement is to the true
value.
• This is restricted or limited by the accuracy
of the measuring instrument.
• The ruler is marked in centimetres, so any
length measured with it can only be given
to the nearest centimetre.
Limit of Accuracy
• For each of these measuring scales, state the
size of one unit on the scale and state the limit of
accuracy.
(a) The size of one unit is 1 kg. The limits of
accuracy are ±0.5 × 1 kg = ±0.5 kg.
(b) The size of one unit is 5 mL. The limits of
accuracy are ±0.5 × 5 mL = ±2.5 mL.
Area
• The Area of a Shape is the Amount of
Surface that is Enclosed by the shape
Area
• Can use grid paper to determine size of area
• Area = 4cm2
Area = 3 squares + ½ square + ½ square
= 4 cm 2
Converting units of area
• 1 cm = 10 mm
• 1 cm2 = 10 × 10 mm2 = 100 mm2
• (double the number of zeros)
• 1 m = 100 cm
• 1 m2 = 100 × 100 cm2 = 10 000 cm2
• (double the number of zeros)
• 1 m = 1000 mm
• 1 m2 = 1000 × 1000 mm = 1 000 000 mm2
• (double the number of zeros)
Conversions of Units
• 1cm2
= 100mm2
• 1m2
= 10 000cm2
• 1m2
= 1 000 000mm2
Investigation of Area of Triangles
• Area of right-angled triangles
• You will need 1-cm grid paper.
• a On your grid paper, draw a rectangle 6 cm by 4 cm.
• b Cut the rectangle in half along a diagonal. What shape
have you made?
• c Area of rectangle = ×
= cm2
• d What is the area of each triangle?
• What do you notice regarding the area of the triangle
and the area of the rectangle?
Area of squares, rectangles and
triangles
• Area of square = side × side
• = s × s
• = s2
• Area of rectangle = length × breadth
• = l × b
• Area of triangle = ½ × base × height
• = ½ × b × h
Examples
• 1 What is the area of this square?
• Solution
• Area = s × s
• = 3.2 × 3.2
• = 1024 cm2
• 2 What is the area of this rectangle?
• Solution
• Area = l × b 6 cm = 60 mm
• = 60 × 5
• = 300 mm2
Area of a Triangle
• 1 Find the area of this triangle.
• Solution
• Area of triangle = ½ × b × h
• = ½ × 8 × 6
• = 24 m2
• Note: The length of 7 m was not required to find this
triangle’s area.
• 2 Find the area of this triangle.
• Solution
• Area of triangle = ½ × b × h
• = ½ × 4.2 × 3
• = 6.3 cm2
Areas of composite shapes
• Find the area of this shape.
• Solution
• Method 1
• Area of shape = area of rectangle Y + area
of square X
• = (6 × 2) + (3 × 3)
• = 12 + 9
• = 21 cm2
• Method 2
• This can also be done by subtracting
areas.
• Area of shape = area of rectangle S − area
of square R
• = 6 × 5 − 3 × 3
• = 30 − 9
• = 21 cm2
What about this shaded area?
• Area of purple shape = area of big rectangle
− area of small rectangle
• = (75 × 45) − (32 × 24)
• = 3375 − 768
• = 2607 mm2
• What shapes can you see?
• Solution
• Divide the shape into a
triangle and a rectangle.
• Area of shape = area of rectangle + area of
triangle
• = (16 × 14) + (½ × 14 × 14)
• = 224 + 98
• = 322 cm2 224cm2
A = ½bh
98cm2
Measuring Large Areas
• 1 hectare is about the size of 2 football fields
• 1 hectare = (100 × 100) m2
• 1 ha = 10 000 m2
• 1 square kilometre is a square 1km by 1km
• 1 km2 = 1000m x 1000m
= 1 000 000 m2
= 100 hectares (ha)
• A nature reserve has an area of 9 577 000 000 m2.
• a What is its area in hectares? b What is its area in square
kilometres?
• Solution
• a Area of reserve = 9 577 000 000 m2
(1ha = 10000m2
)
• = (9 577 000 000 ÷ 10 000) ha
• = 957 700 ha
• The area of the reserve is 957 700 hectares.
• b Area of reserve = 9 577 000 000 m2 (1 km2 =
1 000 000m2
)
• = (9 577 000 000 ÷ 1 000 000) km2
• = 9577 km2
• The area of the reserve is 9577 square kilometres.

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Length and Area of geometric shapes.pptx

  • 3. Limits of accuracy • The accuracy of a measurement is how close that measurement is to the true value. • This is restricted or limited by the accuracy of the measuring instrument. • The ruler is marked in centimetres, so any length measured with it can only be given to the nearest centimetre.
  • 4. Limit of Accuracy • For each of these measuring scales, state the size of one unit on the scale and state the limit of accuracy. (a) The size of one unit is 1 kg. The limits of accuracy are ±0.5 × 1 kg = ±0.5 kg. (b) The size of one unit is 5 mL. The limits of accuracy are ±0.5 × 5 mL = ±2.5 mL.
  • 5. Area • The Area of a Shape is the Amount of Surface that is Enclosed by the shape
  • 6. Area • Can use grid paper to determine size of area • Area = 4cm2 Area = 3 squares + ½ square + ½ square = 4 cm 2
  • 7. Converting units of area • 1 cm = 10 mm • 1 cm2 = 10 × 10 mm2 = 100 mm2 • (double the number of zeros) • 1 m = 100 cm • 1 m2 = 100 × 100 cm2 = 10 000 cm2 • (double the number of zeros) • 1 m = 1000 mm • 1 m2 = 1000 × 1000 mm = 1 000 000 mm2 • (double the number of zeros)
  • 8. Conversions of Units • 1cm2 = 100mm2 • 1m2 = 10 000cm2 • 1m2 = 1 000 000mm2
  • 9. Investigation of Area of Triangles • Area of right-angled triangles • You will need 1-cm grid paper. • a On your grid paper, draw a rectangle 6 cm by 4 cm. • b Cut the rectangle in half along a diagonal. What shape have you made? • c Area of rectangle = × = cm2 • d What is the area of each triangle? • What do you notice regarding the area of the triangle and the area of the rectangle?
  • 10. Area of squares, rectangles and triangles • Area of square = side × side • = s × s • = s2 • Area of rectangle = length × breadth • = l × b • Area of triangle = ½ × base × height • = ½ × b × h
  • 11. Examples • 1 What is the area of this square? • Solution • Area = s × s • = 3.2 × 3.2 • = 1024 cm2 • 2 What is the area of this rectangle? • Solution • Area = l × b 6 cm = 60 mm • = 60 × 5 • = 300 mm2
  • 12. Area of a Triangle • 1 Find the area of this triangle. • Solution • Area of triangle = ½ × b × h • = ½ × 8 × 6 • = 24 m2 • Note: The length of 7 m was not required to find this triangle’s area. • 2 Find the area of this triangle. • Solution • Area of triangle = ½ × b × h • = ½ × 4.2 × 3 • = 6.3 cm2
  • 13. Areas of composite shapes • Find the area of this shape. • Solution • Method 1 • Area of shape = area of rectangle Y + area of square X • = (6 × 2) + (3 × 3) • = 12 + 9 • = 21 cm2
  • 14. • Method 2 • This can also be done by subtracting areas. • Area of shape = area of rectangle S − area of square R • = 6 × 5 − 3 × 3 • = 30 − 9 • = 21 cm2
  • 15. What about this shaded area? • Area of purple shape = area of big rectangle − area of small rectangle • = (75 × 45) − (32 × 24) • = 3375 − 768 • = 2607 mm2
  • 16. • What shapes can you see? • Solution • Divide the shape into a triangle and a rectangle. • Area of shape = area of rectangle + area of triangle • = (16 × 14) + (½ × 14 × 14) • = 224 + 98 • = 322 cm2 224cm2 A = ½bh 98cm2
  • 17. Measuring Large Areas • 1 hectare is about the size of 2 football fields • 1 hectare = (100 × 100) m2 • 1 ha = 10 000 m2 • 1 square kilometre is a square 1km by 1km • 1 km2 = 1000m x 1000m = 1 000 000 m2 = 100 hectares (ha)
  • 18. • A nature reserve has an area of 9 577 000 000 m2. • a What is its area in hectares? b What is its area in square kilometres? • Solution • a Area of reserve = 9 577 000 000 m2 (1ha = 10000m2 ) • = (9 577 000 000 ÷ 10 000) ha • = 957 700 ha • The area of the reserve is 957 700 hectares. • b Area of reserve = 9 577 000 000 m2 (1 km2 = 1 000 000m2 ) • = (9 577 000 000 ÷ 1 000 000) km2 • = 9577 km2 • The area of the reserve is 9577 square kilometres.