Lesson 3 c reciprocal of a complex number is polar form
Download as DOCX, PDF0 likes280 views
To find the reciprocal of a complex number z = r cis θ in polar form, the modulus of the reciprocal is 1/r and the argument is -θ. The reciprocal is equal to 1/r cis -θ, where r is the modulus and θ is the argument of the original complex number z.
1 of 1
Download to read offline
More Related Content
More from jenniech (20)
Ad
Recently uploaded (20)
Ad
Lesson 3 c reciprocal of a complex number is polar form
- 1. Reciprocal of a Complex Number in Polar form Let z = r cis 𝜃 and 𝑧. 1 𝑧 =1 Suppose that 1 𝑧 = 𝛽𝑐𝑖𝑠𝛾 so 𝑧. 1 𝑧 =1 is remember that 1cis 0 = 1 𝑟𝛽𝑐𝑖𝑠( 𝜃 + 𝛾) = 1 𝑐𝑖𝑠 0 What is an expression for the modulus? What is an expression for the arguments? What can you say about 1 𝑧 =