Linear Equations and Graphing - Extra Practice
- 1. Name Date Master 6.20 Extra Practice 1 Lesson 6.1: Solving Equations Using Models 1. Use a model to solve each equation. Verify the solution. a) 7x = 56 b) 45 = 9x c) –x = 4 d) –9 = 3x 2. Use a model to solve each equation. Verify the solution. a) 5x + 4 = 44 b) 7 + 2x = 1 c) 30 = 4x – 6 d) –2x + 8 = 0 3. Five less than six times a number is 13. Let n represent the number. a) Write an equation you can use to solve for n. b) Use a model to solve the equation. What is the number? c) Verify the solution. 4. Jack and Diane went to the movies. They each paid the same amount for an admission ticket. Together, they spent $12 on snacks. The total cost of admission and snacks for Jack and Diane was $26. How much was each admission ticket? a) Choose a variable. Write an equation you could use to solve this problem. b) Use a model to solve the equation. c) Verify the solution. 5. Use a model to solve each equation. Verify the solution. a) 4x + 3 = 23 b) –4x + 3 = 23 c) 4x – 3 = –23 d) –4x – 3 = –23 e) 3x – 4 = 23 f) –3x – 4 = 23 The right to reproduce or modify this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 2. Name Date Master 6.21 Extra Practice 2 Lesson 6.22 Solving Equations Using Algebra Master 6.2: 1. Solve each equation. Verify the solution. Lesson 6.3: Solving Equations Involving Fractions a) 4x = 32 b) –35 = –5x 1. c) –48 = 8xequation. Verify the solution. Solve each t = 54 d) 9x = 7 a a) b) =9 4 3 2. Solve each equation. Verify c solution. b the a) –8a 1111 = 27 c) =+ d) = 12 7 6 b) 12b + 21 = 93 2. c) –42 = 5c – 27 Solve each equation. Verify the solution. d) d – 15 = –45 6f f a) = –8 b) = 10 3. 5 Solve each equation. Verify– 6 solution. the k a) 2x – 7 = 9 q c) = –11 d) = –12 b) − 2 + 6 = –14 –4x 3 c) 6x – 7 = –19 3. d) –7x – 8 = 13 the chicken pieces in the dish are wings. There are 7 wings. One-quarter of How many chicken pieces are in the dish? 4. Solve eachan equation you can use to solve the problem. a) Write equation. Verify the solution. a) 2a + 3 the equation. b) Solve = 4 b) 15 = 10 + 2b c) Verify the solution. c) 3 = 5c – 6 4. d) 9f –each1 Solve 7 = equation. Verify the solution. 5. Write an equation you can use to answer each question. n p Solve the equation. Verify the solution. a) – 2 = 10 b) 4 – = 13 3 5 a) Five more than two times a number is 17. t What is the number? n c) + 8 = –5 d) –17 + =9 b) Six less than five times a number 3 29. −9 − is 5. For each is the number? an equation. What sentence, write Solve the equation to find the number. 6. a) A Grade 8 divided by –4 is 7. The number students had a graduation dinner. They paid a flat rate of $125 for the use of the hall, plus $13 for each student who attended. The total cost of the dinner was $944. b) Add 4 to students attended the –3 and the sum is –2. How many a number divided by dinner? c) Subtract aequation you could use to solve the problem. is 5. a) Write an number divided by 6 from 1 and the difference 6. b) Solve thestudent’s work. Rewrite a correct and complete algebraic solution if necessary. Check this equation. Verify the solution. 7. Use thist information: – 24 = –6 −6 Ice rental: $150 Skate rental: $3 a) Write a problem that can be solved using an equation. t b) Write the 24 + 24 = then solve the problem. – equation, –6 + 24 −6 t = 18 −6 The right to reproduce or modify this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada t = –3
- 3. Name Date Master 6.23 Extra Practice 4 Lesson 6.4: The Distributive Property 1. Draw a rectangle to show that 7(x + 3) and 7x + 21 are equivalent. 2. Draw algebra tiles to show that 2(n – 5) and 2n – 10 are equivalent. 3. Expand. a) 5(x + 6) b) 7(5 – e) c) 3(–x + 8) d) –4(6 – e) e) 8(–2n + 4) f) –3(11y + 7) g) 7(5n – 4) h) –4(–11y + 3) 4. Lottery tickets are sold by a local charity to raise money for cancer research. Each ticket costs $100. Some people pay with a $100 bill and some pay with a $100 cheque. Write two expressions you can use to calculate the total amount of money collected. Let b represent the number of $100 bills received. Let c represent the number of $100 cheques received. 5. Which pairs of expressions are equivalent? Explain your reasoning. a) 4x + 60 and 4(x + 15) b) c + 4 and 4 + c c) 4 + 2b and 6b d) 3(a + 5) and 8 + 3a 6. A school uniform consists of a shirt and a pair of shorts. A shirt costs $22. A pair of shorts costs $15. a) Write two different expressions to find the cost of supplying 8 students with uniforms. b) Evaluate each expression. Which expression did you find easier to evaluate? Justify your choice. 7. Expand. a) 2(3 + 4y + 7) b) 3(9a – 5 – 6) c) –9(–4 – 7c + 10) The right to reproduce this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 4. Name Date Master 6.24 Extra Practice 5 Lesson 6.5: Solving Equations Involving the Distributive Property 1. Solve each equation using the distributive property. Verify the solution. a) 5(a + 2) = –5 b) 4(p – 6) = –4 c) 10(y + 3) = 10 d) 7(r – 6) = 7 2. Solve each equation. Verify the solution. a) –7(b + 6) = –84 b) –5(q –11) = 70 c) –9(d – 3) = –45 d) –6(f – 5) = 36 3. At the fair, 5 friends each bought an $8 meal voucher and one ice-cream voucher. The total cost of the vouchers was $55. What was the price of an ice-cream voucher? a) Choose a variable to represent the price of an ice-cream voucher. Write an equation to model this problem. b) Solve the equation using the distributive property. c) Verify the solution. Explain your thinking in words. 4. Scott bought 54 m of fencing to enclose a rectangular plot of land. The width of the rectangular plot is 12 m. Assume Scott uses all the fencing. What is the length of the rectangular plot of land? a) Choose a variable to represent the length of the rectangular plot of land. Write an equation to model this problem. b) Solve the equation using the distributive property. c) Verify the solution. Explain your thinking in words. 5. Heather chose an integer. She added 9, then multiplied the sum by –4. The product was –16. Which integer did Heather choose? a) Write an equation you can use to solve the problem. b) Solve the equation. c) Verify the solution. 6. Solve each equation. Verify the solution. a) –7(a + 3) = –14 b) –5(7 – r + 11) = 10 c) –7(b – 3) = –13 d) –6(–3 + t – 5) = 10 The right to reproduce or modify this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 5. Name Date Master 6.25 Extra Practice 6 Lesson 6.6: Creating a Table of Values 1. Copy and complete each table of values. a) y = x + 5 b) y = x – 1 c) y = –2x x y x y x y 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 2. Copy and complete each table of values. a) y = 2x – 5 b) y = –3x + 1 c) y = –2x – 5 x y x y x y –3 –3 –3 –2 –2 –2 –1 –1 –1 0 0 0 1 1 1 2 2 2 3 3 3 3. The equation of a linear relation is: y = –3x + 8 Some ordered pairs in the relation are: (–1, 11), (0, 8), (1, ), (2, 2), ( , –1), (4, ) Find the missing numbers in the ordered pairs. 4. The cost of admission to a fair is $10, plus $3 per ride. An equation for this relation is C = 10 + 3r, where r represents the number of rides a person goes on, and C represents the total cost of admission and rides. a) Use the equation to create a table of values. b) Harvey went on 13 rides. How much did Harvey spend on admission and rides? c) Stephanie spent $31 on admission and rides. How many rides did Stephanie go on? 5. These ordered pairs are in the same linear relation. (–3, –11), (–2, –9), (–1, ), (0, –5), ( , –3), (2, ), (3, ) Find the missing numbers in the ordered pairs. Describe the strategy you used. The right to reproduce this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 6. Name Date Master 6.26 Extra Practice 7 The right to reproduce or modify this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 8. Lesson 6.7: Graphing Linear Relations Master 6.27 1. Each graph below is a graph of a linear relation. Describe the relationship between the variables in each graph. a) y = –6x + 1 b) y = 5x – 1 2. Graph each relation for integer values of x from –3 to 3. a) y = x b) y = –x c) y = –2x + 5 d) y = 2x + 5 3. Here is a graph of the linear relation y = –2x + 8. Each point on the graph is labelled with an ordered pair. Some numbers in the ordered pairs are missing. Find the missing numbers. Explain how you did this. 4. The cost of admission to a fair is $10, plus $3 per ride. An equation for this relation is C = 10 + 3r, where r represents the number of rides a person goes on, and C represents the total cost of admission and rides. a) Make a table of values for the relation. b) Graph the relation. c) Describe the relationship between the variables in the graph. d) Find the ordered pair on the graph that shows the number of rides Josh went on when his cost of admission and rides was $22. Extra Practice Answers Extra Practice 1 – Master 6.20 4. a) Let c represent the cost of admission. An equation is: 2c + 12 = 26 Lesson 6.1 1. a) x = 8 b) x = 5 c) x = –4 d) x = –3 b) n = 7; each admission ticket was $7.00. 2. a) x = 8 b) x = –3 c) L.S. = 2(7) + 12 = 14 + 12 = 26 = R.S. c) x = 9 d) x = 4 5. a) x = 5 b) x = –5 3. a) 6n – 5 = 13 c) x = –5 d) x = 5 b) n = 3; the number is 3. e) x = 9 f) x = –9 c) Left side = 6(3) – 5 = 18 – 5 = 13 = Right side The right to reproduce or modify this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 9. Name Date t Extra Practice 2 – Master 6.21 Then, (–6)( − 6 ) = (18)(–6) Lesson 6.2 t = –108 1. a) x = 8 b) x = 7 c) x = –6 d) x = 6 2. a) a = –2 b) b = 6 Extra Practice 4 – Master 6.23 c) c = –3 d) f = –5 Lesson 6.4 3. a) x = 8 b) x = 5 1. c) x = –2 d) x = –3 4. a) a = , or 0.5 b) b = , or 2.5 c) c = , or 1.8 d) f = 5. Let n represent the number. 2. a) 2n + 5 = 17; n = 6 b) 5n – 6 = 29; n = 7 6. a) Let n represent the number of students. 3. a) 5x + 30 b) 35 – 7e 125 + 13n = 944 c) –3x + 24 d) –24 + 4e b) n = 63; 63 students e) –16n + 32 f) –33y – 21 Left side = 125 + 13n = 125 + 13(63) = g) 35n – 28 h) 44y – 12 125 + 819 = 944 = Right side 4. 100(b + c) or 100b + 100c 7. a) Ice rental at the local skating rink is $150 for 2 h. 5. a) Yes; 4(x + 15) = 4x + 4(15) = 4x + 60 Skate rental is $3 per person. The Grade 8 class b) Yes; when you add, order does not matter. went skating. All students rented skates. The total c) No; only like terms can be added. cost was $231. How many students went skating? Since 4 and 2b are not like terms, b) 150 + 3n = 231 4 + 2b ≠ 6b n = 27; 27 students went skating. d) No; 3(a + 5) = 3a + 15 ≠ 8 + 3a 6. a) 8(22) + 8(15) or 8(22 + 15) Extra Practice 3 – Master 6.22 b) 8(22) + 8(15) = 176 + 120 = 296 Lesson 6.3 8(22 + 15) = 8(37) = 296 1. a) t = 28 b) a = 27 7. a) 8y + 20 c) b = 77 d) c = 72 b) 27a – 33 2. a) d = –40 b) f = –60 c) 63c – 54 c) k = 22 d) q = –36 3. Let c represent the number of chicken pieces in the dish. Extra Practice 5 – Master 6.24 c Lesson 6.5 a) 4 = 7 1. a) a = –3 b) p = 5 b) c = 28, there are 28 chicken pieces c) y = –2 d) r = 7 in the dish. 2. a) b = 6 b) q = –3 1 c) d = 8 d) f = –1 c) It makes sense because of the pieces are 1 4 3. Let i represent the price of one ice-cream wings and 4 of 28 is 7. voucher in dollars. 4. a) n = 36 b) p = –45 a) 5(8 + i) = 55 c) t = 117 d) n = –78 n b) i = 3; each ice-cream voucher was $3. 5. a) −4 = 7; n = –28 c) $3 makes sense because the cost of a meal n voucher and an ice-cream voucher is b) −3 + 4 = –2; n = 18 $8 + $3 = $11. There were 5 friends, so the n total cost of the vouchers would be c) 1 – 6 = 5; n = –24 5 × $11 = $55. 6. The solution is correct until the last line. 4. a) Let l represent the length of the rectangular The student multiplied the left side by –6 and plot of land in metres. divided the right side by –6. Both sides should have 54 = 2(l + 12) been multiplied by –6. b) l = 15; the plot of land has length 15 m. t −6 = 18 The right to reproduce this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 10. c) 15 m makes sense because the perimeter of the c) rectangular plot of land is: 15 m + 12 m + 15 m + 12 m = 54 m 5. a) Let i represent the integer. –4(i + 9) = –16 b) i = –5; the integer is –5. c) Left side = –4(–5 + 9) = –4(4) = –16 = Right side 34 19 5 –10 6. a) a = –1b) r = 20c) b = d) t = 7 3 2. a) Extra Practice 6 – Master 6.25 –11 Lesson 6.6 1. a) b) b) c) –11 3. (1, 5), (3, –1), (4, –4) 4. a) b) $49 c) Stephanie went on 7 rides. The right to reproduce or modify this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada
- 11. Name Date 5. (–1, –7), (1, –3), (2, –1), (3, 1) d) I looked at the number patterns: –3, –2, –1, 0, 1, 2, 3 and –11, –9, –7, –5, –3, –1, 1 Extra Practice 7 – Master 6.26 Lesson 6.7 1. a) As x increases by 1, y decreases by 6. The graph is a line that goes down to the right. b) As x increases by 1, y increases by 5. The graph is a line that goes up to the right. 3. (–2, 12), (1, 6), (2, 4) 2. a) I used the patterns in the graph: As x increases by 1, y decreases by 2. 4. a) b) b) c) c) As r increases by 1, C increases by 3. The graph is a line that goes up to the right. d) (4, 22); Josh rode on 4 rides. The right to reproduce this page is restricted to purchasing schools. This page may have been modified from its original. Copyright © 2008 Pearson Education Canada