paschen law
1 .Objective :
If a voltage differential is supplied to a gas as
shown in the setup (Figure 1), an electric field
is formed. If the electric field applied is strong
enough, an avalanche process (the Townsend
avalanche) is started which leads to the
breakdown of the gas and the formation of
plasma. This document describes the physics
of this process and derives the law (Paschen’s
law) that predicts the voltage differential that
needs to be supplied in order to create the
plasma.
2. Description:
As the voltage difference is applied, the electric field
will accelerate any free charges that exist. Free
electrons exist in the system due to random events
from a variety of mechanisms including the
triboelectric effect or through astronomical particles
traversing the vessel and ionizing neutral particles. If
an electron can gain more than the ionizing energy
of the gas, UI (approximately 14eV for Nitrogen), the
electron can ionize the neutral particle and create a
new free electron and a free ion. The new free
electron can repeat the process and create a chain
reaction called the Townsend Avalanche. The ion is
accelerated towards the cathode and as it hits it
there is a chance that it will
paschen law
4 Derivation of Paschen’s Law:
Quantitatively, the electron avalanche can be
described using the rate of ionization per unit
length, α. For example, if α = 2cm−1 then
within a cm of electron travel along the x-
axis, there will, on average, be 2 collisions
with neutral particles that result in ionizing
events. This results in the following equation
describing the increase of electron current
density, Γe(x):
dΓe(x) = Γe(x)αdx, ……(1)
which integrates to:
Γe(x) = Γe(0)e αx …….(2)
Since there is no current leaving or entering the
vessel except through the electrodes, and there is
no charge accumulation, the continuity equation
results in:
Γ(0) = Γ(d),……………. (3)
that is, the current density at the cathode (x = 0) is
the same as that at the anode (x = d). Assuming a
single ion species, Equation 3 can be rewritten as:
Γe(0) + Γi(0) = Γe(d) + Γi(d)……. (4)
Γi(0) = Γe(d) − Γe(0) + Γi(d)……(5)
Using the fact that there is no input of ions
from the anode, Γi(d) = 0. Using this
constraint, and substituting Equation 2 into
Equation 5 results in:
Γi(0) = Γe(0)(e^ αd − 1)……(6)
As an ion reaches the cathode, the
probability of it releasing a secondary
electron is given by the coefficient γ,
therefore:
Γe(0) = γΓi(0)…...(7)
At the threshold point where the secondary
emission sustains the plasma and the
Townsend Avalanche is formed, Equations 6
and 7 are balanced and Γi(0) can be
substituted, leading to:
Γe(0) γ = Γe(0)(e αd − 1)….(8)
1/γ = e αd − 1…(9)
αd = ln (1 + 1/γ)…(10)
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THANK YOU!

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paschen law

  • 2. 1 .Objective : If a voltage differential is supplied to a gas as shown in the setup (Figure 1), an electric field is formed. If the electric field applied is strong enough, an avalanche process (the Townsend avalanche) is started which leads to the breakdown of the gas and the formation of plasma. This document describes the physics of this process and derives the law (Paschen’s law) that predicts the voltage differential that needs to be supplied in order to create the plasma.
  • 3. 2. Description: As the voltage difference is applied, the electric field will accelerate any free charges that exist. Free electrons exist in the system due to random events from a variety of mechanisms including the triboelectric effect or through astronomical particles traversing the vessel and ionizing neutral particles. If an electron can gain more than the ionizing energy of the gas, UI (approximately 14eV for Nitrogen), the electron can ionize the neutral particle and create a new free electron and a free ion. The new free electron can repeat the process and create a chain reaction called the Townsend Avalanche. The ion is accelerated towards the cathode and as it hits it there is a chance that it will
  • 5. 4 Derivation of Paschen’s Law: Quantitatively, the electron avalanche can be described using the rate of ionization per unit length, α. For example, if α = 2cm−1 then within a cm of electron travel along the x- axis, there will, on average, be 2 collisions with neutral particles that result in ionizing events. This results in the following equation describing the increase of electron current density, Γe(x): dΓe(x) = Γe(x)αdx, ……(1)
  • 6. which integrates to: Γe(x) = Γe(0)e αx …….(2) Since there is no current leaving or entering the vessel except through the electrodes, and there is no charge accumulation, the continuity equation results in: Γ(0) = Γ(d),……………. (3) that is, the current density at the cathode (x = 0) is the same as that at the anode (x = d). Assuming a single ion species, Equation 3 can be rewritten as: Γe(0) + Γi(0) = Γe(d) + Γi(d)……. (4) Γi(0) = Γe(d) − Γe(0) + Γi(d)……(5)
  • 7. Using the fact that there is no input of ions from the anode, Γi(d) = 0. Using this constraint, and substituting Equation 2 into Equation 5 results in: Γi(0) = Γe(0)(e^ αd − 1)……(6) As an ion reaches the cathode, the probability of it releasing a secondary electron is given by the coefficient γ, therefore: Γe(0) = γΓi(0)…...(7)
  • 8. At the threshold point where the secondary emission sustains the plasma and the Townsend Avalanche is formed, Equations 6 and 7 are balanced and Γi(0) can be substituted, leading to: Γe(0) γ = Γe(0)(e αd − 1)….(8) 1/γ = e αd − 1…(9) αd = ln (1 + 1/γ)…(10)