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String Matching with Finite
        Automata
      Aho-Corasick String Matching




         By Waqas Shehzad
          Fast NU Pakistan
String Matching

    Whenever you use a search engine, or
    a “find” function like grep, you are
    utilizing a string matching program.
    Many of these programs create finite
    automata in order to effectively search
    for your string.
 
Finite state machines
A finite state machine (FSM, also
 known as a deterministic finite
 automaton or DFA) is a way of
 representing a language
 we represent the language as the set
 of those strings accepted by some
 program. So, once you've found the
 right machine, we can test whether a
 given string matches just by running it.
How it works
   We'll draw pictures with circles and arrows. A
    circle will represent a state, an arrow with a
    label will represent that we go to that state if
    we see that character.
   A finite automaton accepts strings in a
    specific language. It begins in state q 0 and
    reads characters one at a time from the input
    string. It makes transitions (φ) based on
    these characters, and if when it reaches the
    end of the tape it is in one of the accept
    states, that string is accepted by the
    language.
Example
   Example, that could be used by the C preprocessor (a part of most C compilers)
    to tell which characters are part of comments and can be removed from the input




   They can be viewed as just being a special kind of graph, and we can use any of
    the normal graph representations to store them.
cont
   One particularly useful representation is a transition
    table: we make a table with rows indexed by states,
    and columns indexed by possible input characters
Finite Automata
A finite automaton is a quintuple (Q, Σ, δ, s,
  F):
 Q: the finite set of states
 Σ: the finite input alphabet
 δ: the “transition function” from QxΣ to
  Q
 s ∈ Q: the start state
 F ⊂ Q: the set of final (accepting) states
Example: nano

   State diagram for finding word “Nano "through grep
    utility.
   Simulating this on the string "banananona“
   We get the sequence of states empty, empty, empty, "n", "na", "nan",
    "na", "nan", "nano", "nano", "nano".
transition table
Running Time of
   Compute-Transition-Function
It takes something like O(m^3 + n) time:
 O(m^3) to build the state table described
 above,
   O(n) to simulate it on the input file.
Aho-Corasick String Matching


     An Efficient String Matching
Introduction
 Locate all occurrences of any of a finite
  number of keywords in a string of text.
 Consists of constructing a finite state
  pattern matching machine from the
  keywords and then using the pattern
  matching machine to process the text
  string in a single pass.
Pattern Matching Machine(1)
 Let K = { y , y ,, ybe a finite set of
            1   2    k
                         }
  strings which we shall call keywords
  and let x be an arbitrary string which we
  shall call the text string.
 The behavior of the pattern matching
  machine is dictated by three functions:
  a goto function g , a failure function f ,
  and an output function output.
String Matching with Finite Automata,Aho corasick,
Pattern Matching Machine(2)
   Goto function g : maps a pair consisting of
    a state and an input symbol into a state or the
    message fail.
   Failure function f : maps a state into a
    state, and is consulted whenever the goto
    function reports fail.
   Output function : associating a set of
    keyword (possibly empty) with every state.
String Matching with Finite Automata,Aho corasick,
   Start state is state 0.
   Let s be the current state and a the
    current symbol of the input string x.
   Operating cycle
       g ( s, a ) = s '
       If               , makes a goto transition, and
        enters state s’ and the next symbol of x
        becomes the current input symbol.
           g ( s, a ) = fail
       If f ( s ) = s' , make a failure transition f. If
              , the machine repeats the cycle with s’
        as the current state and a as the current
        input symbol.
String Matching with Finite Automata,Aho corasick,
Example
 Text: u s h e r s
 State: 0 0 3 4 5 8 9
                    2
 In state 4, since g ( 4, e ) = 5, and the
  machine enters state 5, and finds
  keywords “she” and “he” at the end of
  position four in text string, emits output ( 5)
Example Cont’d
 In state 5 on input symbol r, the machine
  makes two state transitions in its
  operating cycle.
 Since g ( 5, r ) = fail, M enters state 2 = f (. )
                                                 5
  Then since g ( 2, r ) = 8, M enters state 8 and
  advances to the next input symbol.
 No output is generated in this operating
  cycle.
Construction the functions
   Two part to the construction
       First : Determine the states and the goto
        function.
       Second : Compute the failure function.
       Output function start at first, complete at
        second.
Construction of Goto function
 Construct a goto graph like next page.
 New vertices and edges to the graph,
  starting at the start state.
 Add new edges only when necessary.
 Add a loop from state 0 to state 0 on all
  input symbols other than keywords.
String Matching with Finite Automata,Aho corasick,
String Matching with Finite Automata,Aho corasick,
String Matching with Finite Automata,Aho corasick,
String Matching with Finite Automata,Aho corasick,
About construction
   When we determine f ( s ) = s ' we merge the
                                 ,
    outputs of state s with the output of state s’.
   In fact, if the keyword “his” were not present,
    then could go directly from state 4 to state 0,
    skipping an unnecessary intermediate
    transition to state 1.
   To avoid above, we can use the deterministic
    finite automaton, which discuss later.
Time Complexity of Algorithms 1,
          2, and 3
   Algorithms 1 makes fewer than 2n state
    transitions in processing a text string of length
    n.
   Algorithms 2 requires time linearly
    proportional to the sum of the lengths of the
    keywords.
   Algorithms 3 can be implemented to run in
    time proportional to the sum of the lengths of
    the keywords.
Eliminating Failure Transitions
 Using in algorithm 1
 δ ( s, a ), a next move function δsuch that
  for each state s and input symbol a.
 By using the next move function δ , we
  can dispense with all failure transitions,
  and make exactly one state transition
  per input character.
String Matching with Finite Automata,Aho corasick,
String Matching with Finite Automata,Aho corasick,
Conclusion
 Attractive in large numbers of
  keywords, since all keywords can be
  simultaneously matched in one pass.
 Using Next move function
       can reduce state transitions by 50%, but
        more memory.
       Spend most time in state 0 from which
        there are no failure transitions.
Refrences
   Cormen, et al. Introduction to Algorithms. ©1990 MIT Press,
    Cambridge. 862-868.

   Reif, John.
    http://www.cs.duke.edu/education/courses/cps130/fall98/lectures/lec
    t14/node28.html

   Eppstein, David. http://www.ics.uci.edu/~eppstein/161/960222.html

   http://banyan.cm.nctu.edu.tw/computernetwork2/ Network
    Technology Laboratory ( Network Communication labratory),
    Department of Communicaton Engineering, National chiao Tung
    University.

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String Matching with Finite Automata,Aho corasick,

  • 1. String Matching with Finite Automata Aho-Corasick String Matching By Waqas Shehzad Fast NU Pakistan
  • 2. String Matching Whenever you use a search engine, or a “find” function like grep, you are utilizing a string matching program. Many of these programs create finite automata in order to effectively search for your string.  
  • 3. Finite state machines A finite state machine (FSM, also known as a deterministic finite automaton or DFA) is a way of representing a language  we represent the language as the set of those strings accepted by some program. So, once you've found the right machine, we can test whether a given string matches just by running it.
  • 4. How it works  We'll draw pictures with circles and arrows. A circle will represent a state, an arrow with a label will represent that we go to that state if we see that character.  A finite automaton accepts strings in a specific language. It begins in state q 0 and reads characters one at a time from the input string. It makes transitions (φ) based on these characters, and if when it reaches the end of the tape it is in one of the accept states, that string is accepted by the language.
  • 5. Example  Example, that could be used by the C preprocessor (a part of most C compilers) to tell which characters are part of comments and can be removed from the input  They can be viewed as just being a special kind of graph, and we can use any of the normal graph representations to store them.
  • 6. cont  One particularly useful representation is a transition table: we make a table with rows indexed by states, and columns indexed by possible input characters
  • 7. Finite Automata A finite automaton is a quintuple (Q, Σ, δ, s, F):  Q: the finite set of states  Σ: the finite input alphabet  δ: the “transition function” from QxΣ to Q  s ∈ Q: the start state  F ⊂ Q: the set of final (accepting) states
  • 8. Example: nano  State diagram for finding word “Nano "through grep utility.  Simulating this on the string "banananona“  We get the sequence of states empty, empty, empty, "n", "na", "nan", "na", "nan", "nano", "nano", "nano".
  • 10. Running Time of Compute-Transition-Function It takes something like O(m^3 + n) time: O(m^3) to build the state table described above, O(n) to simulate it on the input file.
  • 11. Aho-Corasick String Matching An Efficient String Matching
  • 12. Introduction  Locate all occurrences of any of a finite number of keywords in a string of text.  Consists of constructing a finite state pattern matching machine from the keywords and then using the pattern matching machine to process the text string in a single pass.
  • 13. Pattern Matching Machine(1)  Let K = { y , y ,, ybe a finite set of 1 2 k } strings which we shall call keywords and let x be an arbitrary string which we shall call the text string.  The behavior of the pattern matching machine is dictated by three functions: a goto function g , a failure function f , and an output function output.
  • 15. Pattern Matching Machine(2)  Goto function g : maps a pair consisting of a state and an input symbol into a state or the message fail.  Failure function f : maps a state into a state, and is consulted whenever the goto function reports fail.  Output function : associating a set of keyword (possibly empty) with every state.
  • 17. Start state is state 0.  Let s be the current state and a the current symbol of the input string x.  Operating cycle g ( s, a ) = s '  If , makes a goto transition, and enters state s’ and the next symbol of x becomes the current input symbol. g ( s, a ) = fail  If f ( s ) = s' , make a failure transition f. If , the machine repeats the cycle with s’ as the current state and a as the current input symbol.
  • 19. Example  Text: u s h e r s  State: 0 0 3 4 5 8 9  2  In state 4, since g ( 4, e ) = 5, and the machine enters state 5, and finds keywords “she” and “he” at the end of position four in text string, emits output ( 5)
  • 20. Example Cont’d  In state 5 on input symbol r, the machine makes two state transitions in its operating cycle.  Since g ( 5, r ) = fail, M enters state 2 = f (. ) 5 Then since g ( 2, r ) = 8, M enters state 8 and advances to the next input symbol.  No output is generated in this operating cycle.
  • 21. Construction the functions  Two part to the construction  First : Determine the states and the goto function.  Second : Compute the failure function.  Output function start at first, complete at second.
  • 22. Construction of Goto function  Construct a goto graph like next page.  New vertices and edges to the graph, starting at the start state.  Add new edges only when necessary.  Add a loop from state 0 to state 0 on all input symbols other than keywords.
  • 27. About construction  When we determine f ( s ) = s ' we merge the , outputs of state s with the output of state s’.  In fact, if the keyword “his” were not present, then could go directly from state 4 to state 0, skipping an unnecessary intermediate transition to state 1.  To avoid above, we can use the deterministic finite automaton, which discuss later.
  • 28. Time Complexity of Algorithms 1, 2, and 3  Algorithms 1 makes fewer than 2n state transitions in processing a text string of length n.  Algorithms 2 requires time linearly proportional to the sum of the lengths of the keywords.  Algorithms 3 can be implemented to run in time proportional to the sum of the lengths of the keywords.
  • 29. Eliminating Failure Transitions  Using in algorithm 1  δ ( s, a ), a next move function δsuch that for each state s and input symbol a.  By using the next move function δ , we can dispense with all failure transitions, and make exactly one state transition per input character.
  • 32. Conclusion  Attractive in large numbers of keywords, since all keywords can be simultaneously matched in one pass.  Using Next move function  can reduce state transitions by 50%, but more memory.  Spend most time in state 0 from which there are no failure transitions.
  • 33. Refrences  Cormen, et al. Introduction to Algorithms. ©1990 MIT Press, Cambridge. 862-868.  Reif, John. http://www.cs.duke.edu/education/courses/cps130/fall98/lectures/lec t14/node28.html  Eppstein, David. http://www.ics.uci.edu/~eppstein/161/960222.html  http://banyan.cm.nctu.edu.tw/computernetwork2/ Network Technology Laboratory ( Network Communication labratory), Department of Communicaton Engineering, National chiao Tung University.

Editor's Notes

  • #8:  = Sigma  = delta